Remember that enzymes always accelerate chemical equations, depending on what the enzyme is consisted of. As the enzymes are burned the reaction or amount of chemical reactions decreases.
From the Rutherford's gold foil experiment one can conclude that nucleus was very small in size, as compared to the atoms. In the experiment Rutherford discovered that, the atom contains a very small nucleus where all of its positive charge of the atom is present.
Temperature grasslands have hot summers and cold winters. Summer temperatures can be well over 100 degrees Fahrenheit, while winter temperatures can be as low as -40 degrees Fahrenheit. They typically have between 10 and 35 inches of precipitation a year, much of it occurring in the late spring and early summer. As climate conditions shift geographically so will the distributions of many plants and animals. The relatively flat terrain of grasslands increases vulnerability to climate change impacts, because habitats and species must migrate long distances to compensate for temperature shift.
Answer is: <span>name of the product nuclide is thorium-230.
</span>
<span>Alpha particle is
nucleus of a helium-4 atom, which is made of
two protons and two neutrons.
²³</span>⁴U → ²³⁰Th + α (alpha
particle).
Alpha
decay is radioactive decay in which an atomic
nucleus emits an alpha particle (helium nucleus) and transforms
into an atom with an atomic number that is reduced by
two and mass number that is reduced by four.
Answer:
The maximum amount of work that can be done by this system is -2.71 kJ/mol
Explanation:
Maximum amount of work denoted change in gibbs free energy 
during the reaction.
Equilibrium concentration of B = 0.357 M
So equilibrium concentration of A = (1-0.357) M = 0.643 M
So equilibrium constant at 253 K, ![K_{eq}= \frac{[B]}{[A]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%20%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D)
[A] and [B] represent equilibrium concentrations
When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M
So reaction quotient at this situation, 
We know, 
where R is gas constant and T is temperature in kelvin
Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and 
is 0.555
So, 
= -2710 J/mol
= -2.71 kJ/mol
