This problem is providing the mass of both magnesium metal and oxygen gas and involved in a chemical reaction and asks for the limiting reactant. At the end, it turns out to be identified as magnesium.
<h3>Stoichiometry</h3>
In chemistry, stoichiometry is a widely-used tool we use in order to relate the mass and moles of different chemical substances involved in a chemical reaction. Thus, we consider the following chemical equation between magnesium and oxygen to produce magnesium oxide.
However, when the mass of the both of the reactants is given, one must identify the limiting reactant as the one producing the least of the moles of the product, which means we can use the given grams of the both of the reactants, their molar masses and mole ratios with the product to obtain the aforementioned:
Thus, we can evidence how 24 g of magnesium produce the least of the moles of magnesium oxide, fact validating the magnesium as the limiting reactant and the oxygen as the excess one.
Learn more about stoichiometry: brainly.com/question/9743981
Answer:
True! A transverse wave does move a medium at an obtuse angle to the wave!!
The chemical equation representing the first ionization energy for lithium is given by;
Li → Li + e-
<h2>Further Explanation; </h2><h3>Ionization energy</h3>
- Ionization energy is the energy required to remove outermost electrons from the outermost energy level. Energy is required to remove an electron from an atom.
- The closer an electron is to the nucleus the more energy is required, since the electron is more tightly bound to the atom thus making it more difficult to remove, hence higher ionization energy.
- Ionization energy increases across the periods and decreases down the group from top to bottom.
- Additionally, the ionization energy increases with subsequent removal of a second or a third electron.
<h3>First ionization energy </h3>
- This is the energy required to remove the first electron from the outermost energy level of an atom.
- Energy needed to remove the second electron to form a divalent cation is called the second ionization energy.
<h3>Trends in ionization energy </h3><h3>1. Down the group(top to bottom)</h3>
- Ionization energy decreases down the groups in the periodic table from top to bottom.
- It is because as you move down the group the number of energy levels increases making the outermost electrons get further from the nucleus reducing the strength of attraction to the nucleus.
- This means less energy will be required compared to an atoms of elements at the top of the groups.
<h3>2. Across the period (left to right)</h3>
- Ionization energy increases across the period from left to right.
- This can be explained by an increase in nuclear energy as extra protons are added to the nucleus across the period increasing the strength of attraction of electrons to the nucleus.
- Consequently, more energy is needed to remove electrons from the nucleus.
Keywords: Ionization energy, periodic table, energy levels, electrons
<h3>Learn more about</h3>
Level: High school
Subject: Chemistry
Topic: Periodic table and chemical families
Sub-topic: Ionization energy
Answer:
Final temperature = 1279.25 K
Explanation:
We can solve this using the formula for Charles law since we are given volume and temperature.
From Charles law, we know that;
V1/T1 = V2/T2
Where;
T1 is the initial temperature
V1 is the initial volume
T2 is the final temperature
V2 is the final volume
We are given;
V1 = 2 L
T1 = 301 K
V2 = 8.5 L
Thus, making T2 the subject, we have;
T2 = V2•T1/V1
Plugging in the relevant values;
T2 = 8.5 × 301/2
T2 = 1279.25 K
