A 10.0-g sample of sodium chloride was placed in 10.0 g of water. If 3.85 g of Cl2 was obtained, what was the percent yield of C
1 answer:
You might be interested in
Answer:
1.08 mol/L
Explanation:
Molarity -
Molarity of a substance , is the number of moles present in a liter of solution .
M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = moles ,
w = given mass ,
m = molecular mass .
From the information of the question ,
V = 250 mL
Since ,
1 mL = 1/1000L
V = 0.250 L
w = 48.8 g
As we known , the mass of glucose ,
m = 180g/mol ,
From the above formula , moles is given as ,
substituting the corresponding values ,
n = 48.8g / 180g/mol
n = 0.27 mol
Now , the molarity can be calculated by using the above equation ,
M = n / V
substituting the corresponding values ,
M = 0.27 mol / 0.250 L
M = 1.08 mol/L