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3 years ago

A tank was filled with 225L 156 ml of water

Mathematics

1 answer:

Blababa [14]3 years ago

6 0

Answer:

There are 293 liters and 209 milliliters of water left in the tank.

Step-by-step explanation:

Since a tank was filled with 225L 156 ml of water on the first day and 106 L 215ml of water on the second day, and that 38 L 162ml of water were used by the family members, to find out how much

water is still left in the tank, the following calculation must be performed:

(225,156 + 106,215) - 38,162 = X

331,371 - 38,162 = X

293.209 = X

Thus, there are 293 liters and 209 milliliters of water left in the tank.

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Answer:

1/50

Step-by-step explanation:

Given that:

Three men: 3
Seven women = 7
Total number of people: 7+3 =10

We need to find the probability that no man will be interviewed until at least two women have been interviewed. So there are two possible probabilities are:

1. One man and two women => P(1 man and 2 women) = 3/10*2/9 = 1/15

2. Three women => P(3 women) = 3/10

Hence, the probability in this situation is: 1/15*3/10 = 1/50

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3 years ago

What two numbers multiply to 1/4 and add to -1?

Dominik [7]

Answer:Are there any options?

Step-by-step explanation:

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3 years ago

If O is an angle in standard position and its terminal side passes through the point

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Answer:

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Step-by-step explanation:

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2 years ago

Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

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The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

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Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$

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Probability that Marvin teleports atleast once during the day = $1-\frac{4}{9}=\frac{5}{9}$

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3 years ago