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OlgaM077 [116]
3 years ago
12

Regular quadrilateral pyramid with base edge b=55 mm and lateral edge l = 7cm. Find the sum of all edges

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

50cm or 500mm

Step-by-step explanation:

There are 4 base edges and 4 lateral edges, therefore, multiply the number for both edges by 4 and add.

Considering the fact that we were given two units of measurement, millimeters and centimeters, but we know that there are 10mm (millimeters) in a cm (centimeter) , we can just divide 55 by 10 to get 5.5.

¦

Therefore;

5.5 x 4 = 22

7 x 4 = 28

28 + 22 = 50cm

The diagram can be drawn in order to assist in answering the question.

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When solving a system of equations, how do you determine which method to use?
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Help please i don’t know how to do it
Norma-Jean [14]

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Step-by-step explanation:

\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\

From the initial condition,

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lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

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3 years ago
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