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OlgaM077 [116]
2 years ago
12

Regular quadrilateral pyramid with base edge b=55 mm and lateral edge l = 7cm. Find the sum of all edges

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

50cm or 500mm

Step-by-step explanation:

There are 4 base edges and 4 lateral edges, therefore, multiply the number for both edges by 4 and add.

Considering the fact that we were given two units of measurement, millimeters and centimeters, but we know that there are 10mm (millimeters) in a cm (centimeter) , we can just divide 55 by 10 to get 5.5.

¦

Therefore;

5.5 x 4 = 22

7 x 4 = 28

28 + 22 = 50cm

The diagram can be drawn in order to assist in answering the question.

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3 years ago
A number that has exactly two distinct factors is prime what is the inverse of the statement?
Anastasy [175]

Answer:

Composite number

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A number that has more than 2 distinct factors is a composite number

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8 0
3 years ago
Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.
torisob [31]
Fermat's little theorem states that
a^p≡a mod p

If we divide both sides by a, then
a^{p-1}≡1 mod p
=>
a^{17-1}≡1 mod 17
a^{16}≡1 mod 17

Rewrite
a^{1000000} mod 17  as
=(a^{16})^{62500} mod 17
and apply Fermat's little theorem
=(1)^{62500} mod 17
=>
=(1) mod 17

So we conclude that
a^{1000000}≡1 mod 17

6 0
3 years ago
I need help on this 2 problems please help​
daser333 [38]
<h3>Answer:</h3>

  7)  0.76 is a rational number

  8)  The list of favorable outcomes is {orange pop #1, orange pop #2}.

<h3>Step-by-step explanation:</h3>

7) The product 0.4 × 1.9 is 0.76. This is not an integer, whole number, or natural number. It is a decimal fraction of finite length, so is a rational number.

___

8) Often, a problem of this sort will ask for the probability of an orange pop outcome. This problem doesn't ask that. Rather it asks what the possible orange pop outcomes are. Drawing one orange pop from the box will give you one of ...

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5 0
3 years ago
What is the area of the figure shown?
musickatia [10]

Check the picture below.

now, we're making an assumption that, the two blue shaded region are equal in shape, and thus if that's so, that area above the 14 is 6 and below it is also 6, 14 + 6 + 6 = 26.

so hmm if we simply get the area of the trapezoid and subtract the area of the yellow triangle and the area of the cyan triangle, what's leftover is what we didn't subtract, namely the shaded region.

\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ h=15\\ a=14\\ b=26 \end{cases}\implies A=\cfrac{15(14+26)}{2}\implies A=300 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\stackrel{trapezoid}{300}~~ - ~~\stackrel{yellow~triangle}{\cfrac{1}{2}(26)(9)}~~ - ~~\stackrel{cyan~triangle}{\cfrac{1}{2}(15)(6)}} \\\\\\ 300~~ - ~~117~~ - ~~45\implies 138\qquad \textit{blue shaded area}

8 0
1 year ago
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