<u>Answer:</u> The concentration of KOH solution is 1.215 M
<u>Explanation:</u>
For the given chemical equation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Hence, the concentration of KOH solution is 1.215 M
E = h * f
<span>so f = E / h = (1.99 *10^-19)/*(6.63*10^-34) </span>
<span>=3.00*10^14 Hz </span>
Answer:
0.4 * 10⁻⁶mol
Explanation:
The unit conversion required are ,
1 μ M = 10⁻⁶ M
1 L = 1000 mL
1 mol = 1000 mmol
molarity of a solution is given as -
Molarity (M) = ( w / m ) / V ( in L)
where ,
m = molecular mass ,
w = given mass ,
V = volume of solution ,
Hence , the unit is ,
M = mol / L
from the question ,
0.4 μ M = 0.4 * 10⁻⁶ M
Now,
0.4 * 10⁻⁶ M = 0.4 * 10⁻⁶ mol / L
Since ,
1 L = 1000 mL
and ,
1 mol = 1000 mmol
0.4 * 10⁻⁶ mol / L = 0.4 * 10⁻⁶ * 1000 mol / 1000 mL = 0.4 * 10⁻⁶mol
Answer:
17.8ml-15.6ml is 2.2 ml then convert to cm so 2.2cm^3
I believe the answer is yes