Answer:
a) P = 15993.6 N/m²
b) P' = 11062.24 N/m²
Explanation:
Given:
Density of the mercury, ρ = 13.6 × 10³ kg/m³
The blood pressure reading is given as 120 over 83 mm
a) Now,
The pressure (P) due to a fluid is given as:
P = ρgh
where, g is the acceleration due to the gravity
h is the pressure head
The systolic pressure head from the blood pressure reading is , h = 120 mm = 0.12 m
substituting the value in the formula for pressure,
we get
P = 13.6 × 10³ × 9.8 × 0.12
or
P = 15993.6 N/m²
b) The systolic pressure head from the blood pressure reading is , h' = 83 mm = 0.083 m
substituting the value in the formula for pressure,
we get
P' = 13.6 × 10³ × 9.8 × 0.083
or
P' = 11062.24 N/m²
Here we would use the equation
![f = m \times a](https://tex.z-dn.net/?f=f%20%3D%20m%20%5Ctimes%20a)
When we sub in we would would write it as
![30 = m \times 6](https://tex.z-dn.net/?f=30%20%3D%20m%20%5Ctimes%206)
you would the solve the equation for an answer of 5
the answer is A. The aluminum has 0.84 ohms more resistance.
Answer:
4.88 K.
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 5 moles
Pressure (P) = 1 atm
Volume (V) = 2 L
Gas constant (R) = 0.082 atm.L/Kmol
Temperature (T) =?
The temperature of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1 × 2 = 5 × 0.082 × T
2 = 0.41 × T
Divide both side by 0.41
T = 2 / 0.41
T = 4.88 K
Therefore, the temperature of the gas is 4.88 K.
Answer:
The center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.
Explanation:
Let the reference point be the center of the Earth
![X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m}](https://tex.z-dn.net/?f=X_%7BCm%20%3D%20%5Cfrac%7BM_eX_e%20%2BM_mX_m%7D%7BM_e%2BM_m%7D)
Where;
Xcm is the distance from center of the Earth =?
Me is the mass of the Earth = 6 × 10²⁴ kg
Xe is the center mass of the Earth = 0
Mm is the mass of the moon = 7 × 10²² kg
Xm is the center mass of the moon = 4 × 10⁸ m
![X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m} = \frac{M_e(0) +M_mX_m}{M_e+M_m} = \frac{ M_mX_m}{M_e+M_m}}\\\\X_C_m = \frac{7 X 10^{22}*4X10^8}{6X10^{24}+7X10^{22}} =\frac{28 X10^{30}}{607X10^{22}}\\\\ X_C_m = 4.613 X10^6 m](https://tex.z-dn.net/?f=X_%7BCm%20%3D%20%5Cfrac%7BM_eX_e%20%2BM_mX_m%7D%7BM_e%2BM_m%7D%20%3D%20%20%5Cfrac%7BM_e%280%29%20%2BM_mX_m%7D%7BM_e%2BM_m%7D%20%3D%20%5Cfrac%7B%20M_mX_m%7D%7BM_e%2BM_m%7D%7D%5C%5C%5C%5CX_C_m%20%3D%20%5Cfrac%7B7%20X%2010%5E%7B22%7D%2A4X10%5E8%7D%7B6X10%5E%7B24%7D%2B7X10%5E%7B22%7D%7D%20%3D%5Cfrac%7B28%20X10%5E%7B30%7D%7D%7B607X10%5E%7B22%7D%7D%5C%5C%5C%5C%20%20X_C_m%20%3D%204.613%20X10%5E6%20m)
Therefore, the center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.