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Law Incorporation [45]
3 years ago
6

a force of 30 N is exerted on cart there is no friction the acceleration of the cart is 6 m/s^2 find the mass of the cart

Physics
1 answer:
Greeley [361]3 years ago
8 0
Here we would use the equation
f = m \times a
When we sub in we would would write it as
30 = m \times 6
you would the solve the equation for an answer of 5
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A satellite orbits Earth. The only force on the satellite is the gravitational force exerted by Earth. How does the satellite’s
bulgar [2K]

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here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location

Explanation:

As we know that gravitational field is defined as the force experienced by the satellite per unit of mass

so we will have

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now in order to find the acceleration of the satellite we know by Newton's II law

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a = \frac{F}{m}

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D = distance between the cars at the start of time = 680 km

v₁ = speed of one car

v₂ = speed of other car = v₁ - 10

t = time taken to meet = 4 h

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v₁ t + v₂ t = D

(v₁ + v₂) t = D

inserting the values

(v₁ + v₁ - 10) (4) = 680

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rate of slower car is given as

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2. A girl whose mass is 55kg stands on a spring weighing machine inside a lift. When the lift starts to ascend, its acceleration
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iris [78.8K]

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F = \frac{kq_1q_2}{d^2}

Here

k = Coulomb's Constant

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d = Distance

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q_1 = 1 \mu C

q_2 = 6 \mu C

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F_{12} = \frac{ (9*10^9 Nm^2/C^2)(1*10^{-6} C)(6*10^{-6} C)}{(1 m)^2}

F_{12} = 54 mN

Force is positive i.e. repulsive

b) As the force exerted on q_2 will be equal to that act on q_1,

F_{21} = F_{12}

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Force is positive i.e. repulsive

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F_{12} = F_{21} = -54 mN

Force is negative i.e. attractive

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3 years ago
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