Answer:
here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
Explanation:
As we know that gravitational field is defined as the force experienced by the satellite per unit of mass
so we will have

now in order to find the acceleration of the satellite we know by Newton's II law

so we will have

so here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
D = distance between the cars at the start of time = 680 km
v₁ = speed of one car
v₂ = speed of other car = v₁ - 10
t = time taken to meet = 4 h
distance traveled by one car in time "t" + distance traveled by other car in time "t" = D
v₁ t + v₂ t = D
(v₁ + v₂) t = D
inserting the values
(v₁ + v₁ - 10) (4) = 680
v₁ = 90 km/h
rate of slower car is given as
v₂ = v₁ - 10
v₂ = 90 - 10 = 80 km/h
To solve this problem we will apply the concepts related to the Electrostatic Force given by Coulomb's law. This force can be mathematically described as

Here
k = Coulomb's Constant
Charge of each object
d = Distance
Our values are given as,


d = 1 m
a) The electric force on charge
is


Force is positive i.e. repulsive
b) As the force exerted on
will be equal to that act on
,


Force is positive i.e. repulsive
c) If
, a negative sign will be introduced into the expression above i.e.


Force is negative i.e. attractive