Answer:
The charge is
Explanation:
From the question we are told that
The mass of each ball is
The distance of separation is
Generally the weight of the each ball is mathematically represented as
where g is the acceleration due to gravity with a value
substituting values
Generally the electrostatic force between this balls is mathematically represented as
given that the the charges are equal we have
So
Now from the question we are told to find the charge when the weight of one ball is equal to the electrostatic force
So we have
=>
Frictional force
Explanation:
Frictional force is a force that opposes the motion between two surfaces that are in contact with one another.
Frictional force opposes motion and it is directed opposite the direction of motion.
There is also frictional force between liquids too.
- Enough force must be supplied in order to overcome this frictional force so as to make a body move.
- In humans, motion wouldn't be possible without the frictional force.
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Answer:
Vf = 23 m/s
Explanation:
First we need to find the distance covered by the motorcycle 2 when it passes motorcycle 1. Using the uniform speed equation for motorcycle 1:
s₁ = v₁t₁
where,
s₁ = distance covered by motorcycle 1 = ?
v₁ = speed of motorcycle 1 = 6.5 m/s
t₁ = time = 10 s
Therefore,
s₁ = (6.5 m/s)(10 s)
s₁ = 65 m
Now, for the distance covered by motorcycle 2 at the meeting point. Since, the motorcycle started 50 m ahead of motorcycle 2. Therefore,
s₂ = s₁ + 50 m
s₂ = 65 m + 50 m
s₂ = 115 m
Now, using second equation of motion for motorcycle 2:
s₂ = Vi t + (1/2)at²
where,
Vi = initial velocity of motorcycle 2 = 0 m/s
Therefore,
115 m = (0 m/s)(10 s) + (1/2)(a)(10 s)²
a = 230 m/100 s²
a = 2.3 m/s²
Now, using 1st equation of motion:
Vf = Vi + at
Vf = 0 m/s + (2.3 m/s²)(10 s)
Vf = 23 m/s
Answer:
a) Final velocity of second bowling pin is <u>2.5m/s</u>.
b) Final velocity of second bowling pin is <u>3 m/s</u>.
Explanation:
Let 'm' be the mass of both the bowling pin -
m = 1.5 kg
Initial velocity of first bowling pin -
In any type of collision between two bodies in horizontal plane , momentum is conserved along the line of impact.
a) Since , initial velocity of second bowling pin is 0 m/s -
Initial momentum ,
Final velocity of first bowling pin , [Considering initial direction of motion of the first bowling pin to be positive]
Let be the final velocity of the second bowling pin.
∴ Final momentum ,
.
Now ,
∴
∴ = 3 - 0.5 = 2.5 m/s
∴ Final velocity of second bowling pin is 2.5 m/s.
b) Since , initial velocity of second bowling pin is 0 m/s -
Initial momentum ,
Final velocity of first bowling pin , [given][Considering initial direction of motion of the first bowling pin to be positive]
Let be the final velocity of the second bowling pin.
∴ Final momentum ,
.
Now ,
∴
∴ = 3 - 0 = 3 m/s
∴ Final velocity of second bowling pin is 3 m/s.
Answer:
A.
Explanation:
momentum depends on weight and speed