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3 years ago

13

Through the process of blank

2 answers:

maksim [4K]3 years ago

8 0

Answer:

Subduction, Trench, Mantle

Explanation:

Alexeev081 [22]3 years ago

6 0

Answer: subduction, trench, and mantle

Explanation:

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3 years ago

If the magnetic field strength is found to be zero between the two wires at a distance of 3.0 cm from the first wire, what is th

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Answer: The magnitude of the current in the second wire 2.67A

Explanation:

Here is the complete question:

Two straight parallel wires are separated by 7.0 cm. There is a 2.0-A current flowing in the first wire. If the magnetic field strength is found to be zero between the two wires at a distance of 3.0 cm from the first wire, what is the magnitude of the current in the second wire?

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3 years ago

To determine a waves frequency you must know the??

lutik1710 [3]

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3 years ago

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As Earth moves around the Sun, its _____ is approximately perpendicular to the force of gravity exerted by the Sun.

Bogdan [553]

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2 years ago

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You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp

GenaCL600 [577]

Answer:

(a)11.24 m/s

(b)7.44 m/s

(c)409 N

(d) $539.55\mu$

(e) 0

Explanation:

The period for 1 circle $2\pi$ of the merry go around is 9.5s. It means the angular speed is:

$\omega = \theta / t = 2\pi / 9.5 \approx 0.661 rad/s$

(a)The speed is

$v = \omega * R = 0.661 * 17 = 11.24 m/s$

(b) Centripetal acceleration:

$a = \frac{v^2}{R} = \frac{11.24^2}{17} = 7.44 m/s^2$

(c) Magnitude of the force that keeps you go around at this acceleration

$F = ma = 55 * 7.44 = 409 N$

(d) let the coefficient of friction by $\mu$ . The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

$F_f = mg\mu = 55*9.81\mu = 539.55\mu$

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2 years ago