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STatiana [176]
3 years ago
6

What is the length of this line? choose 1 answer 9 8 square root of 45 square root of 27

Mathematics
2 answers:
dedylja [7]3 years ago
6 0

Step-by-step explanation:

αηѕωєя

Cloud [144]3 years ago
3 0

Answer:

45

Step-by-step explanation:

Khan

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Would you please help me solve for x it should be a degrees but I’m not sure what it is
Leno4ka [110]

Answer:

x=15º

Step-by-step explanation:

A triangle's angles add up to 180º.

∠A=30º

∠C=180º-45º

∠B=xº

To find ∠B we have to first find ∠C.

Since ∠C does not have an angle, knowing that a straight line is 180º we can subtract it from 45º to find ∠C.

180-45=135

∠C=135º

Now add ∠A and ∠C.

30+135=165

Subtract the sum from 180º

180-165=x

x=15º

Hope this helps :)

6 0
3 years ago
I am very confused with this problem please help me
Tanya [424]

Answer:

The answer is -0.5

Step-by-step explanation:

Divide both side by the numeric factor on the left side then solve

6 0
3 years ago
Read 2 more answers
Order these numbers from largest at the top, to smallest at the bottom.
Andrews [41]

Answer:

2.45x10^3

3.13x10^1

4.987

1.157x10^-4

Step-by-step explanation:

I have assumed that 1.1.57 = 1.157 and the same with the second and third numbers.

3.13 * 10^1 = 31.3

1.157 * 10^-4 = 0.0001157

2.45 * 10^3 = 2450.

5 0
3 years ago
No idea how to do this need help.
Arlecino [84]

Answer:

Hope that helps

Step-by-step explanation:

Brainliest would be much appreciated

3 0
2 years ago
Help me i can’t do this
DerKrebs [107]

Answer:

\huge\boxed{\sf Star = 14}

Step-by-step explanation:

Let snowman be x , star be y and shopping bag be z.

<u>So, the given equations are:</u>

1) x + y = 20                 (Eq. 1)

2) z = x + x      

 z = 2x                         (Eq. 2)

3) z + x = 18                   (Eq. 3)

Put Eq. (2) in Eq. (3)

2x + x = 18

3x = 18

Divide both sides by 3

x = 18 / 3

x = snowman = 6

Now, Put x in (Eq. 1)

6 + y = 20

Subtract 6 to both sides

y = 20 - 6

y = 14

So,

Star = 14

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
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