Explanation:
It is given that,
Radius of circular particle accelerator, r = 1 m
The distance covered by the particle is equal to the circumference of the circular path, d = 2πr
d = 2π × 1 m
(a) The speed of satellite is given by total distance divided by total time taken as :

Let t is the period of the particle.

d = distance covered
s = speed of particle
It is given that the charged particle is moving nearly with the speed of light



(b) On the circular path, the centripetal acceleration is given by :



Hence, this is the required solution.
Answer:
a. 4.9 m
Explanation:
To solve this problem we must take into account that power is defined as the relationship between the work and the time in which the work is done.
P = W/t
where:
P = power = 95 [W] (units of watts)
W = work [J] (units of Joules)
t = time = 6.2 [s]
We can clear the work from the previous equation.
W = P*t
W = 95*6.2 = 589 [J]
Now we know that the work is defined by the product of the force by the distance, therefore we can express the work done with the following equation.
W = F*d
where:
F = force = 120 [N] (units of Newtons)
d = distance [m]
d = W/F
d = 589/120
d = 4.9 [m]