17.8 mL NaOH
<em>Step 1.</em> Write the chemical equation
Fe^(2+) + 2NaOH → Fe(OH)2 + 2Na^(+)
<em>Step 2.</em> Calculate the moles of Fe^(2+)
Moles of Fe^(2+) = 500 mL Fe^(2+) × [0.0230 mmol Fe^(2+)]/[1 mL Fe^(2+)]
= 11.50 mmol Fe^(2+)
<em>Step 3.</em> Calculate the moles of NaOH
Moles of NaOH = 11.50 mmol Fe^(2+) × [2 mmol NaOH]/[1 mmol Fe^(2+)]
= 23.00 mmol NaOH
<em>Step 4.</em> Calculate the volume of NaOH
Volume of NaOH = 23.00 mmol NaOH × (1 mL NaOH/1.29 mmol NaOH)
= 17.8 mL NaOH
Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line
Answer:
(a) when a reaction system reaches a state of equilibrium, the concentration of the products is equal to the concentration of the reactants
Answer:
0.3 s.
Explanation:
Half-life of a first order reaction is defined as the the time taken for any fraction of the reaction to complete is independent of the initial concentration.
Half-life of a first order reaction, t° = 0.693/k
where,
t° = half-life of the reaction
k = rate constant
= 2.3 s^-1
Therefore,
t° = 0.693/2.3
= 0.30 s.
