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jeka57 [31]
3 years ago
5

In the combustion of propanol, what is the molar ratio of propanol (ch3ch2ch2oh) to co2? combustion of propanol: 2ch3ch2ch2oh +

9o2 → 6co2 + 8h2o
Chemistry
1 answer:
maksim [4K]3 years ago
4 0
Propanol molecular formula is C₃H₇OH
the balanced reaction for combustion of propanol is as follows;
2C₃H₇OH + 9O₂ --> 6CO₂  + 8H₂O
Molar ratio of reactants to products can be found out by the stoichiometry.
By looking at the coefficients of reactants and products in the balanced reaction equation, molar ratio can determined.
Therefore the molar ratio of propanol to CO₂ is 2:6, simplified --> 1:3
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What is the IUPAC name for the compound shown below? ch3ch2ch2cnhch2ch3
Nataly_w [17]

We need the  IUPAC name of the given compound.

The IUPAC name is: Hexan-3-imine.

The molecule has six carbon atoms in its skeleton. C=NH bond is attached to the skeleton at 3-position.

The functional group present in this molecule is imine (C=NH).

3 0
3 years ago
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What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution
Nikolay [14]

Answer:

C. 1.17 grams

Explanation:

  • The molarity is the no. of moles of solute in a 1.0 L of the solution.

<em>M = (mass/molar mass)solute x (1000/ V)</em>

M = 0.1 M, mass = ??? g, molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.

∴ mass of NaCl = (M)(molar mass)(V)/1000 = (0.1 M)(58.44 g/mol)(200.0 mL)/1000 = 1.168 g ≅ 1.17 g.

5 0
3 years ago
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Mg + 2AgNO3 -&gt; 2Ag + Mg(NO3)2
9966 [12]

Answer:

Explanation:

We'll assume there is an excess of silver nitrate, so that all 12.0 moles of the magnesium (Mg) will react.

The balanced equation tells us we'll obtain 2 moles of Ag for every 1 mole of magnesium, for a molar ratio of 2/1.

Starting with 12.00 moles Mg, we would therefore hope to find twice that, or 24.00 moles of Ag.

To convert to grams, find the molar mass of Ag from the periodic table.

Ag has a molar mass of 107.9 (to 4 sig figs) grams/mole.

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5 0
2 years ago
How many moles of mgs2o3 are in 193 g of the compound?
Mashutka [201]

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

8 0
3 years ago
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I’m pretty sure it would be B
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