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jeka57 [31]
3 years ago
5

In the combustion of propanol, what is the molar ratio of propanol (ch3ch2ch2oh) to co2? combustion of propanol: 2ch3ch2ch2oh +

9o2 → 6co2 + 8h2o
Chemistry
1 answer:
maksim [4K]3 years ago
4 0
Propanol molecular formula is C₃H₇OH
the balanced reaction for combustion of propanol is as follows;
2C₃H₇OH + 9O₂ --> 6CO₂  + 8H₂O
Molar ratio of reactants to products can be found out by the stoichiometry.
By looking at the coefficients of reactants and products in the balanced reaction equation, molar ratio can determined.
Therefore the molar ratio of propanol to CO₂ is 2:6, simplified --> 1:3
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For an alloy that consists of 33.5 wt% Pb and 66.5 wt% Sn, what is the composition (a) of Pb (in at%), and (b) of Sn (in at%)? T
Tju [1.3M]

Answer:

Pb: 22.4 at%

Sn: 77.6 at%

Explanation:

It is possible to find at% of Pb and Sn converting mass in moles using molar mass assuming a basis of 100g, thus:

Pb: 33.5g × (1mol / 207.2g) = <em>0.1617mol</em>

Sn: 66.5g × (1mol / 118.7g) = <em>0.5602mol</em>

<em />

Total moles: 0.1617mol + 0.5602mol = 0.7219mol

Composition in at%:

Pb: 0.1617mol / 0.7219mol × 100 = <em>22.4 at%</em>

Sn: 0.5602mol / 0.7219mol × 100 = <em>77.6 at%</em>

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I hope it helps!

5 0
3 years ago
100 Points! ALSO WILL MARK BRAINLIST IF 100% CORRECT AND HELPFUL !!
Marrrta [24]
<h3><u>Answer</u>;</h3>

= 226 Liters of oxygen

<h3><u>Explanation</u>;</h3>

We use the equation;

LiClO4 (s) → 2O2 (g) + LiCl, to get the moles of oxygen;

Moles of  LiClO4;

(500 g LiClO4) / (106.3916 g LiClO4/mol)

= 4.6996 moles

Moles of oxygen;

But, for every 1 mol LiClO4, two moles of O2 are produced;

= 9.3992 moles of Oxygen

V = nRT / P

= (9.3992 mol) x (8.3144621 L kPa/K mol) x (21 + 273) K / (101.5 kPa)

= 226 L of oxygen

5 0
3 years ago
What is the total energy needed to boil 255 grams of water, given that the
nexus9112 [7]

Answer:

  • <u>575,000 J</u>

Explanation:

<u>1) Convert the mass of water into number of moles</u>

  • Molar mass of water: 18.015 g/mol

  • Number of moles, n = mass in grams / molar mass

        n = 255 g / 18.015 g/mol = 14.15 mol

<u>2) Use the formula E = n × ΔH vap</u>

This is, you have to multiply the molar ΔH vaporization by the number of moles to find the total energy to boil the given amount of water.

  • E = 14.15 mol × 40,650 J/mol = 575,395.5 J

<u>3) Round to the correct number of significant figures.</u>

The mass of water is the measurement with the least number of significant figures (3), so you must report the answer with 3 significant figures,

  • E = 575,000 J ← answer
3 0
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lbvjy [14]
He is the only one that includes only mollecules
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Hope this answer will help you.

6 0
3 years ago
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