Answer:
17.46× 10²³ molecules
Explanation:
Given data:
Mass of acetic acid = 172.90 g
Number of molecules = ?
Solution:
First of all we will calculate the number of moles of acetic acid :
Number of moles = mass / molar mass
Number of moles = 172.90 g/ 60.1 g/ol
Number of moles = 2.9 mol
Now the given problem will solve by using Avogadro number.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ molecules
2.9 mol × 6.022 × 10²³ molecules / 1 mol
17.46× 10²³ molecules
Avogadro number:
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
Answer:
Explanation:
Hello,
In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:
- Moles of carbon are contained in the 9.582 grams of carbon dioxide:
- Moles of hydrogen are contained in the 3.922 grams of water:
- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:
Finally, we compute the percent by mass of oxygen:
Regards.
2 hydrogen and 2 chlorine on the reactant side(left of the arrow)
There is only 1 H and 1Cl on the products side so the balanced equation would be;
H2 + Cl2 —> 2 HCl
The characteristic is uniformity.
<h3>Uniformity of money</h3>
Money is said to be uniform because irrespective of the nature it exists, the same amount must have the same purchasing power.
For example, a dollar in paper form and a dollar in coin form must be able to buy the same 1 dollar worth of goods.
Thus, a dollar bill, irrespective of its age, has the same purchasing power as a new, crisp dollar bill.
More on uniformity of money can be found here: brainly.com/question/17039370
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Answer:
Roughly C100 H140 N3 O
Explanation:
Gilsonite is a bituminous product that resembles shiny black obsidian.
It contains more than 100 elements.
Its mass composition varies but is approximately 84 % C, 10 % H, 3 % N, and 1 % O.
Its empirical formula is roughly C100 H140 N3 O.
