Answer:
-21 kJ·mol⁻¹
Explanation:
Data:
H₃O⁺ + OH⁻ ⟶ 2H₂O
V/mL: 50 50
c/mol·dm⁻³: 1.0 1.0
ΔT = 4.5 °C
C = 4.184 J·°C⁻¹g⁻¹
C_cal = 50 J·°C⁻¹
Calculations:
(a) Moles of acid
So, we have 0.050 mol of reaction
(b) Volume of solution
V = 50 dm³ + 50 dm³ = 100 dm³
(c) Mass of solution
(d) Calorimetry
There are three energy flows in this reaction.
q₁ = heat from reaction
q₂ = heat to warm the water
q₃ = heat to warm the calorimeter
q₁ + q₂ + q₃ = 0
nΔH + mCΔT + C_calΔT = 0
0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0
0.050ΔH + 1883 + 225 = 0
0.050ΔH + 2108 = 0
0.050ΔH = -2108
ΔH = -2108/0.0500
= -42 000 J/mol
= -42 kJ/mol
This is the heat of reaction for the formation of 2 mol of water
The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.
1. NaF, Na₂S, Na₃P, Na₂O
2. MgF₂, MgS, Mg₃P₂, MgO
3. AlF₃, Al₂S₃, AlP, Al₂O₃
<h3>Further explanation</h3>
Given
Ionic charge
Required
The formula of binary ionic compounds
Solution
Ionic compounds consisting of cations (ions +) and anions (ions -)
Ionic compounds usually consist of metal cations and non-metal anions
Metal: cation, positively charged.
Nonmetal: negatively charged
The anion cation's charge is crossed
The ionic compounds :
1. NaF, Na₂S, Na₃P, Na₂O
2. MgF₂, MgS, Mg₃P₂, MgO
3. AlF₃, Al₂S₃, AlP, Al₂O₃
Yes, that's correct. It's the tepid latitude.
Answer:
: kinetic energy is the energy transformation that occurs in a hot balloon.
Explanation:
Hot air balloons use a propane burner that converts chemical energy to thermal energy. The hot air is less dense than than the colder air and it lifts the balloon
