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wlad13 [49]
3 years ago
12

Can some help me with this i really don't under stand it you can Have brainliest

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

this ez put some over to left and the rest right

Explanation:

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Imagine a 15kg block moving with a speed of 20m/s. Calculate the kinetic energy of this block.
SSSSS [86.1K]

The kinetic energy formula is;

  • KE=\frac{m.v^2}{2}

The variable m represents the mass. Its unit is kilogram. We are informed that the mass of the object is 15kg. The variable v represents the linear velocity. Its unit is meter per second. We are informed that the linear velocity of the object is 20m/s. Let's find the kinetic energy of the object by substituting these values in the formula.

  • KE=\frac{15kg.(20m/s)^2}{2}
  • 2.KE=15kg.400m^2/s^2
  • 2.KE=(6000)kgm^2/s^2
  • KE=(3000)kgm^2/s^2=3000J
5 0
1 year ago
A solution contains an unknown amount of dissolved magnesium. Addition of
Scrat [10]

Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg²⁺: 1 mole
  • Na₂CO₃: 1  mole
  • MgCO₃: 1 mole
  • Na⁺: 2 moles

The molar mass of the compounds is:

  • Mg²⁺: 24.3 g/mole
  • Na₂CO₃: 106 g/mole
  • MgCO₃: 84.3 g/mole
  • Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
  • Na₂CO₃: 1 mole ×106 g/mole= 106 grams
  • MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
  • Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

4 0
2 years ago
How many moles of N2O5 are needed to produce 7.90 g of NO2? 2N2O5 = 4NO2 + O2
miv72 [106K]
Moles of N2O5 = moles of NO2 * ( 2 moles of N2O5 / 4 moles of NO2
3 0
3 years ago
Read 2 more answers
Ava’s best friend has an indoor cat. Ava notices that she sneezes every time that she visits her friend. Ava suspects that she i
zlopas [31]

Answer:

I say for her to test her suspicion by going to see an allergist to diagnose the allergy.

7 0
3 years ago
Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is
Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal =  C_{134}H_{96}O_{9}NS

Molecular mass of coal = (134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm

Let’s calculate the mass of nitrogen in coal

Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}

Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = 4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0
3 years ago
Read 2 more answers
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