Answer:
Explanation:
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In this case, we can represent the chemical reaction as:
In such a way, since the mass of the obtained silver chloride is 93.9 mg, we can compute the chloride ions in the ground water by using the following stoichiometric procedure whereas the molar mass of chloride ions and silver chloride are 35.45 g/mol and 143.32 g/mol respectively:
Finally, for the given volume of water in liters (0.100L), we compute the required concentration:
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It’s A: C2H2N (basically you count how many C, H and N there are)
Answer:
Explanation:
Mᵣ: 58.44 278.11
Pb(NO₃)₂ + 2NaCl ⟶ PbCl₂ + 2NaNO₃
m/g: 26.3
1. Moles of NaCl
(b) Moles of PbCl₂
(c) Theoretical yield of PbCl₂
(d) Percent yield
<span>Soln:
•t: in min
•Q(t): quantity of dye in the tank at time t
•r in= 0: rate of dye poured into the tank per min. Since it is fresh water, so it
is zero.
•r out= density of dye×rate of fluid =Q/900×9: rate of dye flowing out.
•Q(0) = 1×900 g: initial amount of dye in the tank.
•{dQ/dt=rin-rout= 0-Q100 Q(0) = 900g•Q(t)=Ce-1/100t
•Q(0) = 900, C= 900, Q(t) = 900e-1/100t
•Q(t) = 0.01·Q(0), Q(0)e-1/100t= 0.01×Q(0),-t100= ln 0.01, t= 460min</span>
It's the quality of shining by reflecting light