A chemist determined by measurements that moles of calcium sulfide participate in a chemical reaction. Calculate the mass of cal
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Answer: The concentrations of at equilibrium is 0.023 M
Explanation:
Moles of =
Volume of solution = 1 L
Initial concentration of =
The given balanced equilibrium reaction is,
Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of at equilibrium is 0.023 M