Answer:
18 sq. unit
you can draw it on no. line
actually it's rectangle with l=3 and b=6
Answer:
A = 12a - 24
B = 2x² + 10x
C = 45x - 45
D = 6x² - 3x²
Step-by-step explanation:
You can solve all of these by distributing the first number/variable into the parenthesis. Just multiply the number outside the parenthesis by each of the terms inside the parenthesis.
Answer:
it is not possible you cannot divide by zero
The area of the triangle XYZ is 29.1 square units
Explanation:
Given that the measurements of the sides of the triangle XYZ are
,
and ![m\angle X=34^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20X%3D34%5E%7B%5Ccirc%7D)
We need to determine the area of the triangle XYZ
<u>Area of the triangle:</u>
The area of the triangle can be determined using the formula,
![Area=\frac{1}{2} yz \ sin X](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B1%7D%7B2%7D%20yz%20%5C%20sin%20X)
Substituting the values, we get,
![Area=\frac{1}{2}(13)(8) \ sin 34](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B1%7D%7B2%7D%2813%29%288%29%20%5C%20sin%2034)
Simplifying, we get,
![Area=\frac{1}{2}(104) (0.56)](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B1%7D%7B2%7D%28104%29%20%280.56%29)
Multiplying the terms, we get,
![Area=\frac{58.24}{2}](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B58.24%7D%7B2%7D)
Dividing the terms, we have,
![Area=29.12](https://tex.z-dn.net/?f=Area%3D29.12)
Rounding off to the nearest tenth, we get,
![\text {Area}=29.1](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%7D%3D29.1)
Thus, the area of the triangle XYZ is 29.1 square units.