The probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
Given a fair dice and tossing a fair coin sixteen times.
We have to find the probability that the total number of heads in all the coin tosses equals 12.
The probability lies between 0 and 1.
Probabiltiy of coming head when the coin is tossed 1 time is 0.5 and probability of coming tails is also 0.5.
Let X shows the sum of heads while tossing.
P(X=12)=?
We can find the probability using binomial theorem.
=
We have to toss sixteen times and out of 16 times we need head 12 times.
=16!/12!4!*0.00024*0.0625
=1820*0.000015
=0.0273
Hence the probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
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Answer: 3<em>n</em> ants
Step-by-step explanation:
If there are n ants one month, and the ants triple every month, then next month there will be 3<em>n</em> ants.
We can multiply 3 by <em>n</em> to show it tripling.
To test this, 3(10,000) = 30,000 and 3(270,000) = 810,000, which corresponds to what you've filled out in the table.
Answer:
14.625
Step-by-step explanation:
As per the situation the solution of mean and standard deviation change, based on all 12 samples is represented below:-
Mean of all 12 samples is shown below:-


So, the Mean = 23.5
and now,
The Standard deviation of all 12 samples is shown below:-
![= \sqrt{\frac{1}{12}} (36-23.5)^2+(14-23.5)^2+(21-23.5)^2+(39-23.5)^2+(11-23.5)^2+(2-23.5)^2+(33-23.5)^2+(45-23.5)^2+(34-23.5)^2+(17-23.5)^2+(1-23.5)^2+(29-23.5)^2}]](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7B12%7D%7D%20%2836-23.5%29%5E2%2B%2814-23.5%29%5E2%2B%2821-23.5%29%5E2%2B%2839-23.5%29%5E2%2B%2811-23.5%29%5E2%2B%282-23.5%29%5E2%2B%2833-23.5%29%5E2%2B%2845-23.5%29%5E2%2B%2834-23.5%29%5E2%2B%2817-23.5%29%5E2%2B%281-23.5%29%5E2%2B%2829-23.5%29%5E2%7D%5D)
= 14.625
Therefore, we used the above equation to reach the answer.
Answer:
c
Step-by-step explanation:
hope it helps
Answer:
BCF and DCA
Step-by-step explanation: