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MariettaO [177]
3 years ago
13

You throw a ball at a height of 5 feet above the ground. The height h (in feet) of the ball after t seconds can be modeled by th

e equation, h=(-16t)^2 + 44 + 5.
The question is:
After how many seconds does the ball reach a height of 15 feet?
WILL GIVE BRAINLIEST IF ANSWERED CORRECTLY
Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:?

Step-by-step explanation:

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A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

8 0
3 years ago
Solve by substitution<br> 3x-4y=-4<br> y=2x-4
dybincka [34]

Answer:

x=4 and y=4

Step-by-step explanation:

From first function we have:

3x - 4y =  - 4 \\ 4y = 3x  + 4

And from the second one:

y = 2x - 4 \\ 4y = 8x - 16

Substitute them:

4y = 3x + 4 \\ 4y = 8x - 16 \\  \\ 0 =  - 5x + 20 \\ x = 4 \\ y = 4

7 0
3 years ago
Suppose you are given a cube made of magnesium (mg) metal of edge length 2.15 cm. (a) calculate the number of mg atoms in the cu
SVETLANKA909090 [29]

solution:

a) To calculate the volume of cube of edge 1.0cm

Volume= (edge)³

=(100cm) ³

= 1cm³

To find the mass of MG atoms  

Density = mass/volume

Mass of mg = 1.74g/cm³ x 1cm³

       = 1.74g

To find the number of mg atoms,

Molar mass of mg = 24.31g

24.31g mg contain 6.022 x 10²³ atoms of mg  

1.74g mg contain = 6.022 x 10²³mg atoms/24.31g mg x 1.74g mg

    = 0.4310 x 10²³mg atoms

    = 4.31 x 10²² mg atoms

B) to find the volume occupied by mg atoms  

    Total volume of cube = 1 cm³

    Volume occupied by mg atoms  

  = 74% of 1cm³

=74/100 x 1cm³= 0.74cm³

To find the volume of 1 mg atom  

4.31 x 10²² mg atoms occupy 0.74 cm³

1 atom will occupy 0.74cm³

1 atom will occupy = 0.74cm³/4.31 x 10²²mg atoms x 1mg atom

volume of 1 mg atom = 0.1716 x 10⁻²²cm²

Volume of 1 mg atom = 4/3 π³ in the form of sphere.

4/3πr³ = 0.1716 x 10⁻²²cm³

R³ = 0.1716 x 10⁻²²cm³x 4/3 x 7/22

R³ = 0.04095 x 10⁻²²cm³

R = 0.1599 x 10⁻⁷cm

1 = 10⁻¹⁰cm

 = 0.1599 x 10⁻⁷cm

 = 1pm/1 x 10⁻¹⁰cm  x 0.1599 x 10-7cm

= 1.599 x 10² pm  

R= 1.6 x 10²pm


3 0
3 years ago
Julian has to read 4 articles for school. He has 8 nights to read them. He decides to read the same number of articles each nigh
daser333 [38]

<u><em>Answer:</em></u>

a. He will have to read half an article per night

b. Fraction of the reading assignment read each night = \frac{0.5}{4}=\frac{1}{8}

<u><em>Explanation:</em></u>

<u>Part a:</u>

<u>We are given that:</u>

number of articles to read = 4 articles

number of nights = 8 nights

To get the number of articles that he should read per night, we will simply divide the the number of articles by the number of nights

<u>Therefore:</u>

number of articles to read per night = \frac{4}{8}=\frac{1}{2} articles per night

<u>Part b:</u>

Now, we know that he will read half an article each night from a total of 4 articles

To get the fraction of the reading assignment read each night, we will divide the number of articles read each night by the total number of assignments

<u>Therefore:</u>

Fraction of the reading assignment read each night = \frac{0.5}{4}=\frac{1}{8}

Hope this helps :)

5 0
3 years ago
Nifal earned 9$ for washing two cars .He recived $1 more for the second car.How much was he paid for washing each car?Which two
Sveta_85 [38]

Answer:

Nifal received $ 4 for washing the first car.

Nifal received $ 5 for washing the second car.

4 and 5 have a sum of 9.

Step-by-step explanation:

The problem can be rewritten as follows: Find the sum of two consecutive entire numbers equal to 9. That is:

x + y = 9

y = x+1

Then, by eliminating y:

x + (x+1) = 9

2\cdot x + 1 = 9

Now, let is clear x:

2\cdot x = 8

x = 4

Nifal received $ 4 for washing the first car.

The earning for the second car is: (x = 4)

y = x +1

y = 4 + 1

y = 5

Nifal received $ 5 for washing the second car.

4 and 5 have a sum of 9.

8 0
3 years ago
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