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MariettaO [177]
3 years ago
13

You throw a ball at a height of 5 feet above the ground. The height h (in feet) of the ball after t seconds can be modeled by th

e equation, h=(-16t)^2 + 44 + 5.
The question is:
After how many seconds does the ball reach a height of 15 feet?
WILL GIVE BRAINLIEST IF ANSWERED CORRECTLY
Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:?

Step-by-step explanation:

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Read the question and type your response in the box provided. Your response will be saved automatically.
larisa [96]

Answer:

512

Step-by-step explanation:

8 x 8 x 8 = 512

4 0
3 years ago
Read 2 more answers
F(x) =
Oksana_A [137]

9514 1404 393

Answer:

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Step-by-step explanation:

The applicable derivative formula is ...

  d(u/v) = (v·du -u·dv)/v²

__

  f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²

  f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

__

Similarly, the second derivative is the derivative of f'(x).

  f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴

  f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

4 0
3 years ago
AB = 5x -9; BC= -2x + 12
BaLLatris [955]

Answer:

X=-3

Step-by-step explanation:

5x - 9

-2x + 12

(+) (-)

7x = -21

X= -3

plz mark ice bear as Brainliest

3 0
3 years ago
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