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3 years ago

12

A car moving at 11.6 m/s begins to accelerate at 5.22 m/s/s and reaches a final velocity of 31.5 m/s. How far did it travel duri

ng this acceleration?

1 answer:

mr_godi [17]3 years ago

8 0

Use the kinematic equation,

Vf^2 = Vi^2 + 2aX

31.5^2 = 11.6^2 + 2(5.22)(x)

Solve for x

Answer: 82.2m

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At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36. Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

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Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and $\mu$ be the friction coefficient and m be the mass of car.

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