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Rzqust [24]
3 years ago
13

Here are some numbers

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

11,18,25

Step-by-step explanation:

add 7

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Write the equation in its equivalent logarithmic form.
Oksanka [162]
Logₐx=b means aᵇ=x
reverse

aᵇ=x means logₐx=b
so
2³=x means log₂x=3

I say it is A


4 0
3 years ago
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Can someone please help me
mrs_skeptik [129]

Step-by-step explanation:

5x=4x+12(corresponding angle)

5x-4x=12

x=12

if it is correct answer then please follow me

6 0
3 years ago
What is the product of a+3 and −2a2+15a+6b2?
Arte-miy333 [17]

Answer:

<h3>            -2a³ + 9a² + 6ab² + 45a + 18b² </h3>

Step-by-step explanation:

(a + 3)×(−2a² + 15a + 6b²) =

= a×(−2a² + 15a + 6b²) + 3×(−2a² + 15a + 6b²) =

= -2a³ + <u>15a²</u> + 6ab² - <u>6a²</u> + 45a + 18b² =

= -2a³ + 9a² + 6ab² + 45a + 18b²

8 0
2 years ago
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the speed that a tsunami can travel is modeled by the equation mc025-1.jpg , where s is the speed in kilometers per hour and d i
Flura [38]
The answer is a.0.32 km.

The speed that a tsunami can travel is modeled by the equation is s = 356√d.

It is given:
s = 200 km/h
d = ?

Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562

Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32

Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
5 0
3 years ago
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How do if find y=-3x+10 and y=-2+6?
Len [333]
Yep the other one is right it is (4,-2)
3 0
2 years ago
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