What are all the roots of 9i squared

satela [25.4K]

X-5=2-3x+9
x-5=-3x+11
4x-5=11
4x=16
x=4

3 0

3 years ago

An engineering school reports that 59% of its students are male (M), 39% of its students are between the ages of 18 and 20 (A),

KIM [24]

Answer:

.26

Step-by-step explanation:

.59 = M

.39 = A

.24= M∩A

M'∩A'= ?

M'∩A'= (M∪A)' (we call this demorgan's law)

MUA= M+A-M∩A

.59+.39-.24= .74

1-.74= .26

4 0

3 years ago

How to solve -2(1-7n)-5n=34

OLEGan [10]

-2(1-7n)-5n=34

Multiply the bracket by -2

(-2)(1)=-2

(-2)(-7n)=14n

-2+14n-5n=34

-2+9n=34

Move -2 to the other side. Sign changes from -2 to +2.

-2+2+9n=34+2

9n=34+2

9n=36

Divide by 9 for both sides

9n/9=36/9

n=4

Answer: n=4

6 0

3 years ago

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Which sequence of transformations will map figure K onto figure K′? Two congruent kites, figure K and figure K prime, are drawn

elixir [45]

Answer:

The sequence of transformations will map figure K onto figure K′

is the first sequence option (1)

======================================================

Step-by-step explanation:

See the attached figure

as shown in the figure the K' is the image of K by reflection over x-axis

But  We need to know which sequence of transformations will give the same result.

So, we will test the options by any point from K and its image from K'

i.e: we will test the options using the points (6,5) , (6,-5)

(6,5) ⇒ (6,-5)

option (1):

Reflection across x = 4, 180° rotation about the origin, and a translation of (x + 8, y)

(6,5) ⇒ (2,5) ⇒(-2,-5) ⇒ (6,-5)

option (2):

Reflection across x = 4, 180° rotation about the origin, and a translation of (x − 8, y)

(6,5) ⇒ (2,5) ⇒(-2,-5) ⇒ (-10,-5)

option (3):

Reflection across y = 4, 180° rotation about the origin, and a translation of (x + 8, y)

(6,5) ⇒ (6,3) ⇒ (-6,-3) ⇒ (2,-3)

option (4):

Reflection across y = 4, 180° rotation about the origin, and a translation of (x − 8, y)

(6,5) ⇒ (6,3) ⇒ (-6,-3) ⇒ (-14,-3)

As shown: The sequence of transformations will map figure K onto figure K′

is the first sequence option (1)

7 0

4 years ago

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The image of a triangle after it has been dilated with a center at the origin has vertices at A’(-12,6) B’(6,-18) and C’ if the

ArbitrLikvidat [17]

Answer:

scale factor is 2/3.

coordinates of B are (9,-27).

coordinates of C' are : (12,18)

Step-by-step explanation:

The image of a triangle after it has been dilated with a center at the origin has vertices at A’(-12,6) B’(6,-18) and C’ .

Point A has coordinates of (-18,9) and the pre- image of C' point C has coordinates of (18,12).

Clearly when we compare point A and point A' we see that the transformation is a dilation.

let the scale factor of dilation is 'k'.

i.e. A→ A'

i.e. k(-18,9)=(-12,6)

(-18k,9k)=(-12,6)

i.e. -18k=-12

and 9k=6

Hence, on solving we get:

k=2/3

i.e. the scale factor is 2/3.

Also,

we find the coordinates of B(c,d) by:

2/3(c,d)=(6,-18) since B→ B'

2/3×c=6

Hence c=9

and 2/3 ×d=-18

d=-27.

Hence, the coordinates of B are (9,-27).

Also the coordinates of C are (18,12)

Hence, coordinates of C' are:

$(\dfrac{2}{3}\times 18,\dfrac{3}{2}\times 12)\\\\=(12,18)$

Hence, the coordinates of C' are : (12,18)

7 0

3 years ago

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