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malfutka [58]
3 years ago
14

The terminal side of θ in standard position contains the point (–4, 3). Find the exact values of the six trigonometric functions

of θ. (show all of your work) *
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0

Answer:

When we have a rectangular point (x, y), the angle between the x-axis and a ray that connects the origin with this point is given by:

Tan(θ) = y/x.

Cos(θ) = x/(√(x^2 + y^2))

Sin(θ) = y/(√(x^2 + y^2))

So for the point (-4,3) we have:

x = -4

y = 3

√( (-4)^2 + 3^2) = √(16 + 9) = √25 = 5

Then:

Tan(θ) = 3/-4 = -(3/4)

Sin(θ) = 3/5

Cos(θ) = -4/5

And for the other 3 trigonometric functions (the inverses of the 3 above ones) we have:

Ctg(θ) = 1/Tan(θ) = -4/3

Csc(θ) = 1/Sin(θ) = 5/3

Sec(θ) = 1/Cos(θ) = -4/5

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4 0
3 years ago
Principal = 5300=5300 rupees
PSYCHO15rus [73]

Answer:

Using the formula:

A=P+I

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As per the statement:

Principal(P) = 5300 rupees.

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Total amount(A) = 6678 rupees.

Then using above formula we have;

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Subtract 5300 both sides we get;

1378 = I

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I = \$1378

We have to find the time period.

Using formula of Simple interest:

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here, r = 6.5% = 0.065

Substitute the given values top find t:

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