1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zheka24 [161]
3 years ago
12

Which of the following would notbe taken into consideration when describing the quality of a sound? A.The frequency of the overt

ones in the sound B.The source producing the overtones in the sound C.The intensity of the overtones in the sound D.The number of the overtones in the sound
Physics
2 answers:
slavikrds [6]3 years ago
7 0

Answer;

B.The source producing the overtones in the sound

The source producing the overtones in the sound, would not be taken into consideration when describing the quality of a sound.

Explanation;

-The quality of the sound describes those characteristics of sound which allow the ear to distinguish sounds which have the same pitch and loudness

-The quality of a sound depends on its wave form, which varies with the number of overtones, or harmonics, that are present, their frequencies, and their relative intensities.

-The source producing the overtones in the sound does not affect the quality or timbre of the sound, and therefore would not be considered when describing the quality of the sound.

Natalija [7]3 years ago
6 0
<span>the one that should be taken as consideration when describing the quality of a sound is: D.The number of the overtones in the sound Too many overtones indicated that there is too many unrelated sound that make a lot of the sound's part became redundant and unecessary</span>
You might be interested in
Describe how the forces of gravity and friction affect the motion that occurs as you write on this page.
Zinaida [17]

Answer:

Friction is a force that slows down the motion of a moving object. ... Eventually, friction and gravity will work together to stop the motion of the slide. Gravity is a force that pulls two objects toward each other because of their mass. Mass is the measurement of the amount of material (matter) that makes up an object.

6 0
2 years ago
Calculate (a) the torque, (b) the energy, and (c) the average power required to accelerate Earth in 4.0 days from rest to its pr
natima [27]
<h2>Answer:</h2>

Torque = <em>2.05 x 10²⁸ Nm</em>

Energy = <em>3.54 x 10³³ J</em>

Average power = <em>1.02 x 10²⁸ W</em>

<h2>Explanation:</h2>

(a) Torque (τ) is the rotational effect of a given force.  

It is given by

τ = I x α          -------------(i)

Where;

I = rotational inertia of the object

α = angular acceleration of the object.

In this case, the object is the Earth. Therefore,

I = 9.71 x 10³⁷ kg m²

α = ω / t

Where;

ω = angular velocity of earth = 2π rad / day

<em>Since </em>

<em>1 day = 24 hours and 1 hour = 3600seconds</em>

<em>1 day = 24 x 3600 seconds = 86400seconds</em>

<em>=> ω = 2π rad / 86400seconds</em>

<em>=> ω = 7.29 × 10⁻⁵ rad/s</em>

<em />

t = 4 days = 4 x 24 x 3600 seconds = 345600 seconds

=> α = ω / t

=> α = 7.29 × 10⁻⁵ / 345600

=> α = (7.29 × 10⁻⁵) / (3.456 x 10⁵)

=> α = (7.29 × 10⁻⁵⁻⁵) / (3.456)

=> α = (7.29 × 10⁻¹⁰) / (3.456)

=> α = 2.11 × 10⁻¹⁰ rad/s²

Now substitute the values of I and α into equation (i)

τ = 9.71 x 10³⁷ x 2.11 × 10⁻¹⁰

τ = 9.71 x 10²⁷ x 2.11

τ = 20.5 x 10²⁷ Nm

τ = 2.05 x 10²⁸ Nm

(ii) The energy (rotational energy) E is given by;

E = \frac{1}{2} x I x ω

E = \frac{1}{2} x 9.71 x 10³⁷ x 7.29 × 10⁻⁵

E = 35.4 x 10³² J

E = 3.54 x 10³³ J

(iii) The average power P, is given by;

P = E / t

P = 3.54 x 10³³ / 345600

P = 1.02 x 10²⁸ W

5 0
3 years ago
2. A 50 kg diver is standing on the edge of a 15 m high cliff. What is his potential energy?
Lera25 [3.4K]

Answer:

3675 J

Explanation:

Gravitational Potential Energy = \frac{1}{2} × mass × g × height

( g is the gravitation field strength )

Mass = 50 kg

G = 9.8 N/kg ( this is always the same )

Height = 15 m

Gravitational Potential Energy = \frac{1}{2} × 50 ×9.8 × 15

= 3675 J

3 0
3 years ago
At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 44.0 N at the s
BabaBlast [244]

Answer:

Weight at the surface of Jupiter's moon Io is 8.13 N .

Explanation:

Given :

Acceleration due to gravity at the surface of Jupiter's moon is g_m=1.81\ m/s^2 .

Weight of watermelon in earth , W=44\ N .

Acceleration due to gravity at the surface of earth is g=9.81\ m/s^2 .

We know , weight is given by :

W=mg\\m=\dfrac{W}{g}\\\\m=4.49\ kg

Therefore , mass at the surface of Jupiter's moon Io is :

W_m=mg_m\\\\W_m=4.49\times 1.81\\\\W_m=8.13 \ N

Hence , this is the required solution .

6 0
3 years ago
Does plants have prokaryotic cells?
vova2212 [387]
No they have eukaryotic cells
7 0
3 years ago
Read 2 more answers
Other questions:
  • A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the hor
    5·1 answer
  • If the world was not tilted, what would happen to the people living on Earth
    10·2 answers
  • Which state of matter has a definite volume but no definite shape
    14·1 answer
  • What does a Battery and a human have in common?
    11·1 answer
  • Why is evaporation of water greater in summer?
    15·2 answers
  • The clouds that occur at the highest altitude are usually
    6·2 answers
  • H is a chemical_______and H2 is a chemical_______?
    12·1 answer
  • Item 16 The weight w (in pounds) of an object varies inversely with the square of the distance d (in miles) of the object from t
    12·1 answer
  • A net force of 10 N accelerates an object at 5.0 m/s^2. What is the mass of the object? A. 2 kg B. 10 kg C. 5 kg D. 20 kg
    13·1 answer
  • What factors affect the strength and direction of electrical forces?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!