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OleMash [197]
3 years ago
10

To understand the relationships among the parameters that characterize a wave. It is of fundamental importance in many areas of

physics to be able to deal with waves. This problem will lead you to understand the relationship of variables related to wave propagation: frequency, wavelength, velocity of propagation, and related variables. Note that these are kinematic variables that relate to the wave's propagation and do not depend on its amplitude.
------------------------------------

A. Traveling waves propagate with a fixed speed usually denoted as v (but sometimes c). The waves are called __________ if their waveform repeats every time interval T.

-transverse

-longitudinal

-periodic

-sinusoidal
Physics
1 answer:
34kurt3 years ago
3 0

Answer:

The correct option is (c) "periodic wave"

Explanation:

The relationship between the angular frequency and the radial frequency is :

\omega=2\pi f

f is the radial frequency

Frequency, wavelength, velocity of propagation, and related variables do not depend on the amplitude of wave. Travelling waves are also known as periodic wave if their waveform repeats every time interval T. Frequency, wavelength and the speed of wave are the factors that defines traveling waves.

So, the correct option is (c) "periodic wave".

You might be interested in
Two ideal solenoids of radii R and 4 R , respectively, have n turns per meter, and each carries a current of I . Both currents f
telo118 [61]

Answer:

The formula for the calculation of the magnetic field inside a solenoid is

B = μo*n*I

where

μo: vacuum permeability

n: turns per meter

I: current

The magnetic field inside de solenoid is constant. In the case of a small-radius solenoid inside a large-radius solenoid, the magnetic field inside the small-radius solenoid is the magnetic field generated by itself plus the magnetic field generated by the large-radius solenoid. (The radius of the solenoids does not have to be with the instensity of the magnetic field):

BT = Bs + Bl

Bs: magnetic fiel of the small-radius solenoid

Bl: magnetic fiel of the large-radius solenoid

Hence:

BT = 2*μo*n*I

6 0
4 years ago
4. A massless spring hangs from the ceiling, and a mass is hung from the bottom of it. The mass is supported
MrRissso [65]

Answer:

The correct option is C: 0.31 s.

Explanation:

When the mass is then suddenly released we have:

F = k\Delta y

Where:

F is the force

k: is the spring constant

Δy: is the spring displacement

Since the tension in the spring is zero, the force is the weight:

F = mg

Where:

m is the mass of the object

g is the gravity

mg = k\Delta y    (1)

The oscillation period of the spring is given by:

T = 2\pi \sqrt{\frac{m}{k}}    (2)

By solving equation (1) for "k" and entering into equation (2) we have:

T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}}

T = 2\pi \sqrt{\frac{\Delta y}{g}}

Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:

T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s                   

Hence, the oscillation period is 0.31 s.

The correct option is C: 0.31s.

I hope it helps you!                                                                                                      

7 0
3 years ago
A 8.0×104kgspaceship is at rest in deep space. Its thrusters provide a force of 1200kN. The spaceship fires its thrusters for 20
Sladkaya [172]

Answer:

Time = 40 s

It will take the spaceship 40s to coast that distance.

Explanation:

Using the impulse momentum equation;

Impulse = change in momentum

Ft = m(∆v) ........1

Given;

Force F = 1200kN

time of action t = 20s

Mass of spaceship m = 8.0×10^4 kg

∆v = change in velocity

Substituting the values into equation 1;

1200kN × 20s =8.0×10^4 kg × ∆v

∆v = 1200000×20/80000

∆v = 300 m/s

Since it was initially at rest, V0 = 0

Final velocity V2 = 300 + 0

V2 = 300m/s

Time To travel 12 km,

Time = distance/speed

Distance = 12 km = 12000m

Speed = 300m/s

Time = 12000/300

Time = 40 s

It will take the spaceship 40s to coast that distance.

4 0
3 years ago
A radio wave sent from the surface of the earth reflects from the surface of the moon and returns to the earth. The elapsed time
frez [133]

Answer:

7.92 × 10^8 M

8 0
4 years ago
Bumper car A (281 kg) moving
solmaris [256]

use consevation of linear momentum

  • m1v1+m2v2=(M1+M2)V3
  • 281(2.82)+209(-1.72)=(209+281)V2
  • 792.42-359.48=490v3
  • 432.9=490v3
  • V3=0.88m/s
4 0
2 years ago
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