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OleMash [197]
3 years ago
10

To understand the relationships among the parameters that characterize a wave. It is of fundamental importance in many areas of

physics to be able to deal with waves. This problem will lead you to understand the relationship of variables related to wave propagation: frequency, wavelength, velocity of propagation, and related variables. Note that these are kinematic variables that relate to the wave's propagation and do not depend on its amplitude.
------------------------------------

A. Traveling waves propagate with a fixed speed usually denoted as v (but sometimes c). The waves are called __________ if their waveform repeats every time interval T.

-transverse

-longitudinal

-periodic

-sinusoidal
Physics
1 answer:
34kurt3 years ago
3 0

Answer:

The correct option is (c) "periodic wave"

Explanation:

The relationship between the angular frequency and the radial frequency is :

\omega=2\pi f

f is the radial frequency

Frequency, wavelength, velocity of propagation, and related variables do not depend on the amplitude of wave. Travelling waves are also known as periodic wave if their waveform repeats every time interval T. Frequency, wavelength and the speed of wave are the factors that defines traveling waves.

So, the correct option is (c) "periodic wave".

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If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Mrrafil [7]

Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

5 0
3 years ago
A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?
Andrei [34K]
The gravitational constant (G) in its base SI units is

3/2
m
3
k
g
/
s
2


But is often seen written as

⋅
N
⋅
2/2
m
2
/
k
g
2


Where N is the Newton unit. N=kg ⋅
⋅
m/s 2
2


4 0
2 years ago
Is this right? plzz anwser soon
-Dominant- [34]

Answer:

yes

Explanation:

6 0
3 years ago
Read 2 more answers
Suppose a person pushes thumbtack that is 1/5 centimeter long into a bulletin board, and the force (in dynes) exerted when the d
mario62 [17]

Answer:

W = 290.7 dynes*cm

Explanation:

d = 1/5 cm = 0.2 cm

The force is in function of the depth x:

F(x) = 1000 * (1 + 2*x)^2

We can expand that as:

F(x) = 1000 * (1 + 4*x + 4x^2)

F(x) = 1000 + 4000*x + 4000*x^2

Work is defined as

W = F * d

Since we have non constant force we integrate

W = \int\limits^{0.2}_{0} {(1000 + 4000*x + 4000*x^2)} \, dx

W = [1000*x + 2000*x^2 + 1333*X^3] evaluated between 0 and 0.2

W = 1000*0.2 + 2000*0.2^2 + 1333*0.2^3 - 1000*0 - 2000*0^2 - 1333*0^3

W = 200 + 80 + 10.7 = 290.7 dynes*cm

3 0
4 years ago
A certain light truck can go around a flat curve having a radius of 150 m with a maximum spee dof 32.0 m/s. With what maximum sp
Dvinal [7]

Answer

Maximum speed at 75 m radius will be 22.625 m /sec

Explanation:              

We have given radius of the curve r = 150 m

Maximum speed v_{max}=32m/sec

Coefficient of friction \mu =\frac{v_{max}^2}{rg}=\frac{32^2}{150\times 9.8}=0.6965

Now new radius r = 75 m

So maximum speed at new radius v_{max}=\sqrt{\mu rg}=\sqrt{0.6965\times 75\times 9.8}=22.625m/sec

7 0
3 years ago
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