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dolphi86 [110]
3 years ago
8

A recycling bin is in the shape of a right rectangular prism. The bin is 12 meters long, 512 meters wide, and 612 meters tall.

Mathematics
2 answers:
fiasKO [112]3 years ago
3 0

Right rectangular prism is nothing but cuboid.

If l is the length of a rectangular prism, w, its width and h, its height, then the volume of the rectangular prism is V = lwh.

It is given that the length of the recycling bin is 12 meters, its width is 512 meters and height is 612 meters.

Therefore, volume = lwh

= 12 × 512 × 612 cubic meters

= 3760128 cubic meters.

Hence, volume of the recycling bin is 3760128 m^{3}.

WINSTONCH [101]3 years ago
3 0

<u>12 x 5 1/2 x 6 1/2 = 429 cm³</u>

<u>Brainliest please!</u>

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Answer:

I believe it is 384, but I am not positive.

Step-by-step explanation:

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3 years ago
May someone assist me?
raketka [301]

Answer:

<h2><u><em>15 is the answer.</em></u></h2>

Step-by-step explanation:

The side lengths are equal - supposedly

30                          25

?                              ?

25 + ? = 45

-25        - 25

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The question mark should be equal to 15.

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3 0
4 years ago
Find the absolute maximum and absolute minimum values of f on the given interval.
anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

f(x)=xe^{-\frac{x^{2}}{32} } , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

f(x)=xe^{-\frac{x^{2}}{32} }

Using the product rule, first derivative will be:

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} ) = 0

1-\frac{x^{2}}{16}=0

\frac{x^{2}}{16}=1

x^{2}=16

x = ±4

x can't be -4 because it is not in the interval [-2,8].

f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76

f(4)=4e^{-\frac{4^{2}}{32} }=2.42

f(8)=8e^{-\frac{8^{2}}{32} }=1.08

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0
3 years ago
True or false Question in picture?
Sunny_sXe [5.5K]

False. b is the y-intercept.

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