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Fed [463]
3 years ago
7

Hello there :3 Please anwser this Combined gas law problem for me . By the way just anwser #4 for me that’s all . I uploaded the

formulas on my other question if you need to use it . Please help me I don’t understand this please be an expert I will mark brianliest don’t scam me and SHOW ALL THE WORK! I just don’t understand *.* . Will report any links !

Chemistry
1 answer:
stellarik [79]3 years ago
6 0

Answer:

136L

Explanation:

p1v1=p2v2

114 x44.0=37.0x V2

V2=136L

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Which of the following sentences represents a physical change? sugar dissolves in coffee iron rusts gasoline burns in an engine
MAXImum [283]

<u><em>Answer:</em></u>

  • Physical changes example is sugar dissolves in coffee
  • Chemical changes examples are iron rusts, gasoline burns in an engine and a candle burns.

Explanation.

  • Physical changes depend on only physical state, not on composition, which can be separated by physical means while chemical changes depend on composition and only separated by chemical ways.
  • As in case of iron rusting, gasoline and candle burn are cases chemical changes bcz they convert into another substance whose composition is different from other as compare to sugar which has same composition in coffee ,only state is changed from solid to liquid.

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4 years ago
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10. Air is a homogenous mixture of gases. Oxygen is 20% by volume of air typically. What
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Answer:

893 moles

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An ideal gas at STP occupies 22.4 liters. Calculating Oxygen as if it were an ideal gas there are . 893 moles of Oxygen in 20.0 liters.

3 0
3 years ago
Which gas will diffuse at a faster rate, CH4 with a molar mass of 16 g or
vivado [14]

Answer:

CH₄ will diffuse at faster rate.

Explanation:

According to Graham's law,

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It  is given in question the molar mass of CH₄ is 16 g. Thus the square rot of 16 is.

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The molar mass of SO₂ is 64 g and the square root is,

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As it is stated that diffusion rate is inversely related to the square root of molar mass thus the diffusion rate of  SO₂ is lower while methane diffuse faster.

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