1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fed [463]
2 years ago
7

Hello there :3 Please anwser this Combined gas law problem for me . By the way just anwser #4 for me that’s all . I uploaded the

formulas on my other question if you need to use it . Please help me I don’t understand this please be an expert I will mark brianliest don’t scam me and SHOW ALL THE WORK! I just don’t understand *.* . Will report any links !

Chemistry
1 answer:
stellarik [79]2 years ago
6 0

Answer:

136L

Explanation:

p1v1=p2v2

114 x44.0=37.0x V2

V2=136L

You might be interested in
(100 POINTS AND BRAINLYEST)
Blababa [14]

Answer:

Sea level changes due to change in temperature leading to thermal expansion

6 0
3 years ago
Read 2 more answers
The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10-6 M/s.
avanturin [10]

Answer:

The rate would be lower and the concentration of reactants would be lower.

Explanation:

The rate of a chemical reaction depends on the rate constant and the concentration of reactants.

For Ex:

For a reaction experimentally given by A + B ----> C + D

Rate = k[A][B]

where k is the rate constant

          [A] = concentration of reactant A

          [B] = concentration of reactant B

As the reaction proceeds,the concentration of reactant decrease and concentration of products increase.Rate constant k depends only on temperature and activation energy.Hence it will remain constant throughout the reaction assuming that reaction is carried out at constant temperature and pressure.

Hence rate will depend only on concentration of reactants and hence decrease with decrease in concentration of reactants.

8 0
2 years ago
Convert 4.0 cm to mm.
BabaBlast [244]

Answer: 40mm

Explanation:

You would multiply 4.0 by 10.

5 0
2 years ago
Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
2 years ago
Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many
Flauer [41]

Answer : The amount of formaldehyde permissible are, 5.4\times 10^{-6}g

Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L     (1kg/m^3=1g/L)

First we have to calculate the mass of air.

\text{Mass of air}=\text{Density of air}\times \text{Volume of air}

\text{Mass of air}=1.2g/L\times 6.0L

\text{Mass of air}=7.2g

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 5.4\times 10^{-6}g

Thus, the amount of formaldehyde permissible are, 5.4\times 10^{-6}g

8 0
3 years ago
Other questions:
  • What is the rise and fall of ocean water are called
    10·2 answers
  • When water freezes it forms a lattice pattern and ______
    5·1 answer
  • A bike travels 35.896 meters in 6.25 seconds. The average speed is than calculated
    11·2 answers
  • PLEASE HELP!!!! I NEED TO TURN IT IN TODAY!!
    6·1 answer
  • The circuit element whose purpose is to convert electrical energy into another form of energy is the _____. battery resistor fus
    8·2 answers
  • Is mud colloid or suspension??<br> what about muddy water????
    15·2 answers
  • An archaeologist discovers an ancient wooden bowl. which isotope would most likely be used to determine its age?
    10·2 answers
  • How many molecules are there in 8.25 moles of CaHia?
    5·1 answer
  • HELP!!!!<br> please omg
    9·1 answer
  • How do protons determine element identity
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!