Hello there :3 Please anwser this Combined gas law problem for me . By the way just anwser #4 for me that’s all . I uploaded the
formulas on my other question if you need to use it . Please help me I don’t understand this please be an expert I will mark brianliest don’t scam me and SHOW ALL THE WORK! I just don’t understand *.* . Will report any links !
1 answer:
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Answer:
The number of chlorine atoms present in units of gold III chloride is
Explanation:
Formula of Gold (III) chloride:
<em>Avogadro Number</em> : Number of particles present in <u>one mole</u><u> </u>of a substance.
Using,
= 1 mole(0.9999 , nearly equal to 1 )
The given Gold III chloride sample is 1 mole in amount.
= 1 mole of
In this Sample,
1 mole of will give = 3 mole of Chlorine atoms
1 mole of Cl contain =
3 mole of Cl contain =
3 mole of Cl contain =
So,
The number of chlorine atoms present in units of gold III chloride is