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notsponge [240]
3 years ago
14

Any change that alters a substance without changing it into another substance.

Chemistry
1 answer:
Stolb23 [73]3 years ago
5 0
I think its physical change hope this helps
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What two sublevels of orbitals contain valence electrons? (s, p, d, or f)?
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Woodpeckers find insects to eat by pecking holes in trees with their beaks. One day, a woodpecker finds a particular tree that o
bixtya [17]

Answer:

1. Reflex Conditioning

Explanation:

Conditioning is an aspect of learning where a stimulus works effectively in producing a response from an organism. This response becomes regular given the type of reinforcement that is administered to the organism. The reinforcement is usually a reward that is given to the organism.

This is what is observed in the woodpecker.  The stimulus or reinforcement which proves effective in producing a continuous response  from the woodpecker is the abundant supply of the birds favorite bugs. This reinforcement makes it possible for the woodpecker to become conditioned towards returning to the tree.

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3 years ago
The carbon-14 content of a wooden harpoon handle found in an Inuit archaeological site was found to be 61.9% of the carbon-14 co
astraxan [27]

Answer:

3,964 years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

  • The half-life of the element is 5,730 years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(5,730 years) = 1.21 x 10⁻⁴ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 1.21 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 100%).

[A] is the remaining concentration of the sample ([A] = 61.9%).

∴ t = (1/k) ln([A₀]/[A]) = (1/1.21 x 10⁻⁴ year⁻¹) ln(100%/61.9%) = 3,964 years.

7 0
3 years ago
What is the [H+] if the pH is 13.6?
MrRa [10]

Answer:

8???

Explanation:

i honestly don't know???

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