Use the eq. of Young modulus Y=(F/A)/(∆l/lo)
dimana ∆l is the elongation of wire, lo is its initial length.
So ∆l = (F/A)lo/Y.
∆l = (1000N/(6.5 × 10^-7 m^2))×(2.5m)/(2.0 × 10^-11 N/m^2)
Use calculator to finish it.
Answer:
1.6 x
N
Explanation:
If the force between two actual wires has this value, the current is defined to be exactly 1 A.
The force between two parallel wires carrying current can be defined as,
F= μ
L/ 2πd
where,
current
= 1Amp
current
= 2amp
Length 'L'= 1m
distance 'd'= 2.5m
permeability of free space 'μ'= 4πx
N/m
Putting the above values in the equation,
F=( 4πx
x 1 x 2 x 1 )/ 2πx2.5
F= 1.6 x
N
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