Answer:
3) None of the above
Explanation:
In orbital motion
by lepler law:
Planet sweeps out equal area in equal of time, so angular velocity is conserved.
Angular momentum is also conserved,
so option, 3) None of the above is right.
assuming the reference line to measure the height for gravitational potential energy lying at the equilibrium position
m = mass attached to the spring = 10.00 kg
k = spring constant of the spring = 250 N/m
h = height of the mass above the reference line or equilibrium position = 0.50 m
x = compression of the spring = 0.50 m
v = speed of mass = 2.4 m/s
A = maximum amplitude of the oscillation
v' = speed of mass at the maximum amplitude location = 0 m/s
using conservation of energy between the point where the speed is 2.4 m/s and the highest point at which displacement is maximum from equilibrium
kinetic energy + spring potential energy + gravitational potential energy = kinetic energy at maximum amplitude + spring potential energy at maximum amplitude + gravitational potential energy at maximum amplitude
(0.5) m v² + m g h + (0.5) k x² = (0.5) m v'² + m g A + (0.5) k A²
inserting the values
(0.5) (10) (2.4)² + (10) (9.8) (0.50) + (0.5) (250) (0.50)² = (0.5) (10) (0)² + (10) (9.8) A + (0.5) (250) A²
109.05 = (98) A + (125) A²
A = 0.62 m
Hello!
We can use Faraday's Law of Electromagnetic Induction to solve.
ε = Induced emf (4.08 V)
N = Number of loops (?)
= Magnetic Flux (Wb)
t = time (s)
**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.
Now, we know that is analogous to the change in magnetic flux over change in time, or , so:
Rearrange the equation to solve for 'N'.
Plug in the given values to solve.
**Rounding up because we cannot have a part of a loop.
Moon is the answer, it is because of the moon's phases, revolutions, and rotations
The medium is glass (index of refraction: 1.70)
Explanation:
We can solve the problem by using the concept of index of refraction.
The index of refraction of a medium is given by:
where
is the speed of light in a vacuum
v is the speed of light in the medium
For the medium in this problem, we have
So, the index of refraction of this medium is
And looking at tables of index of refraction of various materials, we see that various types of glass have index of refraction of 1.70.
Learn more about refraction here:
brainly.com/question/3183125
brainly.com/question/12370040
#LearnwithBrainly