Answer:
Please mark as Brainliest!!
Explanation:
Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation. When the applied force is released, the whole system returns to its original shape.
Answer:
<h2><em>
34.46m</em></h2>
Explanation:
Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;
v is the final velocity of the bicyclist = 26m/s
u is the initial velocity of the bicyclist = 0m/s
a is the acceleration due to gravity = 9.81m/s
s is the distance covered during travel
Substitute the given parameters into the formula above to get the distance traveled
26² = 0² + 2(9.81)s
676 = 19.62s
Divide both sides by 19.62
676/19.62 = 19.62s/19.62
s = 34.46m
<em>The distance traveled by the bicyclist during the race is 34.46m</em>
Answer:
Explanation:
KE = ½Iω²
ΚΕ = ½(mL²/3)ω²
ΚΕ = ½(0.63(0.82²)/3)4.2²
ΚΕ = 1.24541928
KE = 1.2 J
Answer:
289282
Explanation:
r = Radius of plate = 0.52 mm
d = Plate separation = 0.013 mm
A = Area = 
V = Potential applied = 2 mV
k = Dielectric constant = 40
= Electric constant = 
Capacitance is given by

Charge is given by

Number of electron is given by

The number of charge carriers that will accumulate on this capacitor is approximately 289282.
Answer:
The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Explanation:
Electric potential is given as;
V = E*r
where;
E is the electric field strength, = kq/r²
V = ( kq/r²)*r
V = kq/r
k is coulomb's constant = 8.99 X 10⁹ Nm²/C²
q is the charge of the particles = 1.6 X 10⁻¹⁹ C
r is the distance between the particles = 859 nm
At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm
V = (8.99 X 10⁹ * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)
V = 3.349 X 10⁻³ Volts
Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts