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3 years ago

Given: AABC = ADEF

Mathematics

1 answer:

LenaWriter [7]3 years ago

8 0

Answer: Its C!( 15 units)

Step-by-step explanation:

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What number should be added to 95 to get a sum of −21?

Natali [406]

Answer: -116

Step-by-step explanation: Since negative numbers are involved, the best way to solve this is add 95 and POSITIVE 21. This gives you 116. Since you move from a positive to a negative, the 116 needs to be negative

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4 years ago

Express 8.218.218, point, 21 as a mixed number.

Nikolay [14]

Answer:

8 21/100

Step-by-step explanation:

8.21 is read "eight and twenty-one hundredths". The mixed number "eight and twenty-one hundredths" is written ...

8 21/100

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3 years ago

What is the value of w

ValentinkaMS [17]

Answer: Square root 6 /2

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3 years ago

Solve the inequality − 3 x + 6 > 15

Leviafan [203]

Answer:

The Answer to your question is x<-7 Hope This could Help

Step-by-step explanation:

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3 years ago

Read 2 more answers

6-10 divide, another onee thank you!!

eduard

Answers:

10.) $\displaystyle \pm{5}$

9.) $\displaystyle 1\frac{1}{2}$

8.) $\displaystyle \pm{1\frac{1}{2}}$

7.) $\displaystyle \pm{1\frac{1}{2}}$

6.) $\displaystyle \pm{\frac{1}{2}}$

Step-by-step explanations:

10.) $\displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}$

9.) $\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}$

8.) $\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

7.) $\displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

6.) $\displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}$

I am joyous to assist you at any time.

5 0

2 years ago