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Mandarinka [93]
3 years ago
11

(2x+3y+4z)(4x^2+9y^2+16z^2-6xy-12yz-8zx)

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0
1.1 Factoring: 4x2+9y2+16z2-6xy-12yz-8xz

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -6xy-12yz
Group 2: 16z2-8xz
Group 3: 4x2+9y2

Pull out from each group separately :

Group 1: (x+2z) • (-6y)
Group 2: (x-2z) • (-8z)
Group 3: (4x2+9y2) • (1)


Looking for common sub-expressions :

Group 1: (x+2z) • (-6y)
Group 3: (4x2+9y2) • (1)
Group 2: (x-2z) • (-8z)
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Which equation justifies why seven to the one third power equals the cube root of seven?
Rudiy27

The equation that  justifies why seven to the one third power equals the cube root of seven is seven to the one third power all raised to the third power equals seven to the one third times three power equals seven

<h3>How to solve an equation?</h3>

using indices law,

\sqrt[n]{x}  = x^{1 / n}

Therefore, let's justify

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Hence, the justification is as follows;

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