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2 years ago

Please help me!

Computers and Technology

2 answers:

BaLLatris [955]2 years ago

8 0

Answer:

Choose what you think based on this.

Explanation:

with a for loop:

>>> students = 3

>>> for student in range(students):

>>> print(student)

would output

>>> 0

>>> 1

>>> 2

with a while loop now:

>>> students = 3

>>> student = 0

>>> while student < students:

>>> student = student + 1

>>> print(student)

the for loop is more compact than the while loop. But there may be some times when a you cant do a for loop. The first question is more than likely definite but I don't know the second answer.

Rudik [331]2 years ago

7 0

Answer:

definite, and for

Explanation:

edg 2020 VOTE ME BRAINLIEST OR ELSE!

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// In this exercise, you will be given a variable, it will be called: value

rjkz [21]

Answer:

import java.util.Scanner;

public class Solution {

public static void main(String args[]) {

Scanner scan = new Scanner(System.in);

System.out.println("Enter your value");

int value = scan.nextInt();

greaterThanFive(value);

}

public static void greaterThanFive(int userInput){

System.out.println(userInput > 5);

}

Explanation:

The first line import the Scanner which is use to enable to accept user input.

The class is defined as Solution in the next line. The main method is declared in the next line which signify the beginning of the program.

Then, a scanner object is declared called scan in the next line. Then a prompt is display to the user to input a value. The user input is stored in the variable value. The value is then passed to the method greaterThanFive.

The method greaterThanFive is declared and have just one parameter, the userInput. Inside the method, we output if the userInput is greater than 5 using the logical operator (>).

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3 years ago

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yarga [219]

Answer:

Explanation:

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5 0

3 years ago

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3 years ago

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7 0

2 years ago

Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N

Kryger [21]

Answer:

Here is the C++ program.

#include <iostream> //to use input output functions

using namespace std; // to access objects like cin cout

void chessboard(int N){ // function that takes a number N as parameter generates corresponding board

int i, j;

string black = "B"; // B for black squares

string white = "W"; // W for white squares

for(i=1;i<=N;i++){ //iterates through each column of the board

for(j=1;j<=N;j++){ //iterates through each row of the board

if((i+j)%2==0) // if sum of i and j is completely divisible by 2

cout<<black<<" "; //displays B when above if condition is true

else //if (i+j)%2 is not equal to 0

cout<<white<<" "; } // displays W when above if condition is false

cout<<endl; } } //prints the new line

int main(){ //start of the main function

int num; //declares an integer num

cout << "Enter an integer representing the size of the chessboard: "; //prompts user to enter size of chess board

cin >> num; //reads value of num from user

chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

8 0

3 years ago