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SSSSS [86.1K]
3 years ago
6

Compute the sum 2(2 1/2) + 3(2 1/3) + 4(2 1/4) + 5(2 1/5) +........ + 10(2 1/10)

Mathematics
2 answers:
earnstyle [38]3 years ago
3 0

Answer: 2/15

Step-by-step explanation:Given the sequence An = {1, 3, 5, 7, 9},. (a) what is ... (a) The index of a3 is n = 3 so they're asking me for the third term, which is "5". ... To find the series sum, I'll be adding all the terms, like this: 2(0) + ... List the first four terms of the sequence {an} = {n2}, starting with n = 1. ... {12, 22, 32, 42}. = {1, 4, 9, 16} ... 2 – 4 + 6 – 8 + 10.

DerKrebs [107]3 years ago
3 0

Answer: 53

Step-by-step explanation:

I really don't know how to explain.

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Is floor(x) periodic?
diamong [38]

If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.

The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.

Conclusion: The function floor(x) is <u>not</u> periodic.

4 0
4 years ago
Read 2 more answers
Simplify 2a^2b^3(4a^2+3ab^2-ab)
-BARSIC- [3]
2a^2b^3(4a^2+3ab^2-ab)=? 
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>

Substitute this back into the original equation and you get 
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) = 
<span>2a^3b^3(4a-b+3b^2)
</span>
3 0
3 years ago
How many steps do we take from 0 to -13???
Rus_ich [418]

Answer:

13

Step-by-step explanation:

because thats how u get to 13

6 0
3 years ago
Is − 227 in the sequence below? 13 , 7 , 1 , − 5 , − 11 ,
Papessa [141]

Answer:

Step-by-step explanation:-227 is in The sequence

13,7,1,-5,-11,.....

First term=a=13

Common difference=d=7-13=-6

Checking if -227 is in The sequence

using the formula

Tn=a+dx(n-1)

-227=13+(-6)x(n-1)

-227=13-6n+6

collect like terms

6n=13+6+227

6n=246

Divide both sides by 6

6n/6=246/6

n=41

Therefore -227 is the 41ist term Of The sequence

4 0
4 years ago
83/63 as a mixed number?
JulsSmile [24]
Since 63 goes into 83 once, with a remainder of 20, write the mixed fraction like so: 

1 20/63

Also, because you cannot simplify this answer anymore, this is the final answer. 

Hope this helps!
4 0
3 years ago
Read 2 more answers
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