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valentina_108 [34]
3 years ago
11

What is the answer lol ....

Biology
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

The answer's G

Explanation:

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What do bone marrow and the epidermis have in common
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They are both sites of a new cell form
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Sexual reproduction relies on meiosis instead of mitosis because only meiosis produces diploid sex cells.
tamaranim1 [39]

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Imagine that a toxin is introduced to the body and inhibits the establishment of the proton gradient in the intermembrane space.
jarptica [38.1K]

Answer:

ATP synthase would be unable to produce ATP

Explanation:

ATP synthase depends on the proton gradient in the intermembrane space to enable it to produce ATP. As a consequence of this, the toxin will make it inactive. Oxidative phosphorylation is now inhibited in this case, as opposed to substrate-level phosphorylation.

Pyruvate is a product of glycolysis, and it will not be affected by a toxin. NADH is very important in the establishing of a proton gradient, so it is expected that it would be unable to be oxidized due to the toxin. Protons produced in the conversion of NADH to NAD+ actually establish the proton gradient. If the gradient is absent, NADH is then not likely to be oxidized.

3 0
3 years ago
A sand storage tank used by the highway department for winter storms is leaking. As the sand leaks out, it forms a conical pile.
harina [27]

Answer:

Rate of change of volume of the pile  = 54\pi

Explanation:

Given -

Rate of increase of the base of the pile = 0.75 inches per minute

Height of the pile = 2 * the radius of the base

Let "h"  be the height of the pile and "r" be the radius of the base.

Then h = 2* r

Radius "r" = 6 inches

Rate of change of radius i.e

\frac{dr}{dt} = 0.75

Volume of conical pile

\frac{\pi }{3} * r^2 * h\\= \frac{\pi }{3} * r^2 * 2 * r\\= \frac{\pi }{3} *2* r^3

Change in volume of conical pile

\frac{dV}{dt} =  \frac{dr}{dt}  * \frac{6* \pi * r^2 }{3}

Substituting the value of rate of change of radius, we get -

\frac{dV}{dt}  = 2 * \pi * (6^2) * (0.75)\\\frac{dV}{dt}  = 54 \pi

Rate of change of volume of the pile  = 54\pi

8 0
3 years ago
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