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Nata [24]
3 years ago
11

Is carbonic acid (H2CO3) soluble in water?

Chemistry
2 answers:
NeTakaya3 years ago
8 0

Answer:

it is soluble in water

Explanation:

mark brainliest pliiz cutee:)

nydimaria [60]3 years ago
4 0
Yes it is soluble in water
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What is the molarity of na+ in a solution of nacl whose salinity is 5.6 if the solution has a density of 1.03 g/ml?
pantera1 [17]
Salinity has units of grams NaCl or salt per kilogram solution. We can use the density given and the molar mass of the salt to convert from salinity to molarity. We do as follows:

( 5.6 g / kg ) ( 1.03 kg / L ) ( 1 mol / 58.44 g ) = 0.0987 mol NaCl / L
8 0
3 years ago
A scholar measures 20 mL of room temperature water (22ºC) and adds 80 mL of 75°C water to it, following the
Leni [432]

Answer:

Data is not valid

Explanation:

When two liquids having different temperatures are mixed, regardless of the volumes, the final mix temperature will ALWAYS be between the initial temperature values.

1st Law Thermo => Law of Conservation of Energy => Energy can not be created nor destroyed, only changed in form. Mixing 22°C with 75°C will NOT result in a mix having a final temperature of 80°C.

∑ΔE = 0 => (mcΔT)₁ + (mcΔT)₂ = 0

[(20g)(1cal/g·°C)(Tₓ - 22°C)] + [(80g)(1cal/g·°C)(Tₓ - 75°C)] = 0

=> 20(Tₓ - 22) + 80(Tₓ - 75) = 0

=> 20Tₓ - 440 + 80Tₓ - 75 = 0

=> 100Tₓ = 440 + 75 = 515

=> Tₓ = (515/100)°C = 51.5°C final mix temperature

4 0
3 years ago
What is the suitable way of investigating the different food colourings in some drinks ?
Firlakuza [10]

Answer:

by using the chromatography you can separate different color

6 0
2 years ago
An object was measured by a worker as
Gre4nikov [31]

Answer:

\boxed{2.8 \, \%}

Explanation:

\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%

Data:

Predicted = 17.4 cm

     Actual = 17.9 cm

Calculation:

\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}

6 0
3 years ago
Ammonia, NH3, can be classified as a base because in a chemical reaction with an acid, ammonia will (1 point)produce hydroxide i
olasank [31]
NH will <span>accept a proton and become NH4+

Bases follow </span>B^-+H^+=BH, with B^-=NH_3 in our case.
8 0
3 years ago
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