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Nata [24]
2 years ago
11

Is carbonic acid (H2CO3) soluble in water?

Chemistry
2 answers:
NeTakaya2 years ago
8 0

Answer:

it is soluble in water

Explanation:

mark brainliest pliiz cutee:)

nydimaria [60]2 years ago
4 0
Yes it is soluble in water
You might be interested in
A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . H
maw [93]

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = 5.48\times 10^{-7} \ M

M2 = 484 nM

or,

      = 4.84\times 10^{-7} \ M  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ M1\times V1=M2\times V2

or,

⇒            V2=\frac{M1\times V1}{M2}

By substituting the values, we get

                    =\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}

                    =\frac{339.212}{4.84}

                    =70.08 \ mL

7 0
3 years ago
]The image shows groundwater zones.
11111nata11111 [884]

Answer:

C.) 3 is the correct answer

7 0
3 years ago
Read 2 more answers
Air has a mass of 1.2g and a volume of 4,555ml. What is the density
coldgirl [10]

Answer:

<h2>Density = 0.00026 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density(\rho) =  \frac{mass}{volume}</h3>

From the question

mass of air = 1.2 g

volume = 4,555 mL

Substitute the values into the above formula and solve for the density

That's

<h3>Density =  \frac{1.2}{4555}</h3>

= 0.0002634

We have the final answer as

<h3>Density = 0.00026 g/mL</h3>

Hope this helps you

3 0
3 years ago
Magnesium (average atomic mass = 24.3050 amu) consists of three isotopes with masses 23.9850 amu, 24.9858 amu, and 25.9826 amu.
iris [78.8K]

Answer: The first isotope has a relative abundance of 79% and last isotope has a relative abundance of 11%

Explanation: Given that the average atomic mass(M) of magnesium

= 24.3050amu

Mass of first isotope (M1) = 23.9850amu

Mass of middle isotope (M2)=24.9858amu

Mass of last isotope(M3)= 25.9826amu

Total abundance = 1

Abundance of middle isotope = 0.10

Let abundance of first and last isotope be x and y respectively.

x+0.10+y =1

x = 0.90-y

M = M1 × % abundance of first isotope + M2 × % of middle isotope +M3 ×% of last isotope

24.03050= 23.985× x + 24.9858 ×0.10 + 25.9826×y

Substitute x= 0.90-y

Then

y = 0.11

Since y=0.11, then

x= 0.90-0.11

x=0.79

Therefore the relative abundance of the first isotope = 11% and the relative abundance of the last isotope = 79%

5 0
2 years ago
How many moles of copper are needed to react with sulfur to produce 0.25 moles of copper sulfide
Setler [38]
                                        Cu + S ---> CuS
by reaction                      1 mol           1 mol
from the problem         0.25 mol        0.25 mol
 0.25 mol   Cu
6 0
3 years ago
Read 2 more answers
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