Question

Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five seconds.​

Answer 1

Answer:

E = 75 J

Explanation:

First, we will calculate the total power consumed by the five lamps:

$Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W$

Now, the energy supply can be calculated as follows:

$E = Pt$

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

E = 75 J