Answer
given,
heat added to the gas,Q = 3300 kcal
initial volume, V₁ = 13.7 m³
final volume, V₂ = 19.7 m³
atmospheric pressure, P = 1.013 x 10⁵ Pa
a) Work done by the gas
W = P Δ V
W = 1.013 x 10⁵ x (19.7 - 13.7)
W = 6.029 x 10⁵ J
b) internal energy of the gas = ?
now,
change in internal energy
Δ U = Q - W
Q = 3300 x 10³ cal
Q = 3300 x 10³ x 4.186 J
Q = 1.38 x 10⁷ J
now,
Δ U = 1.38 x 10⁷ - 6.029 x 10⁵
Δ U = 1.32 x 10⁷ J
It would be both speed and direction depending on the man's swing
Answer:
Explanation:
D = 8.27 m ⇒ R = D / 2 = 8.27 m / 2 = 4.135 m
ω = 0.66 rev/sec = (0.66 rev/sec)*(2π rad/1 rev) = 4.1469 rad/s
We can apply the equation
Ff = W ⇒ μ*N = m*g <em>(I)</em>
then we have
N = Fc = m*ac = m*(ω²*R)
Returning to the equation <em>I</em>
<em />
μ*N = m*g ⇒ μ*m*ω²*R = m*g ⇒ μ = g / (ω²*R)
Finally
μ = (9.81 m/s²) / ((4.1469 rad/s)²*4.135 m) = 0.1379
A fan may be used to model an atom because the fan blades form something similar to a electron cloud. But there is really nothing to model the neutrons and protons. Also the fan is flat like where an atom is more 3-D sphere-like.
hope this helps
Ur welcome
have a great day (:
Yes, that's right. It's the 'Planck' length, not the 'Planet' length.
You could easily find these with a web search. But in gratitude
for the bountiful 5 points, I've saved you the trouble.
AND guess what ! By doing that, I learned something, and
you didn't.
Speed of light (c): 299,792,458 meters per second
Gravitational constant (G): 6.67 x 10⁻¹¹ newton-meter²/kilogram²
Planck's Konstant (h): 6.63 x 10⁻³⁴ joule-second
Planck Length: 1.6 x 10⁻³⁵ meter
(about 10⁻²⁰ the size of a proton)
Planck Time: 10⁻⁴³ second
(about the time it takes to travel
a Planck Length at the speed of light)
