Answer : The correct option is (d) 2.73 m
Explanation :
By the 2nd equation of motion,
![s=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
where,
s = distance or height = ?
u = initial velocity = 3.0 m/s
t = time = 0.5 s
a = acceleration due to gravity = ![9.8m/s^2](https://tex.z-dn.net/?f=9.8m%2Fs%5E2)
Now put all the given values in the above equation, we get:
![s=(3.0m/s)\times (0.5s)+\frac{1}{2}\times (9.8m/s^2)\times (0.5s)^2](https://tex.z-dn.net/?f=s%3D%283.0m%2Fs%29%5Ctimes%20%280.5s%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%289.8m%2Fs%5E2%29%5Ctimes%20%280.5s%29%5E2)
![s=2.73m](https://tex.z-dn.net/?f=s%3D2.73m)
Therefore, the correct option is (d) 2.73 m
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