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8_murik_8 [283]
3 years ago
9

Remember to include your data, equation, and work when solving this problem.

Physics
1 answer:
andrezito [222]3 years ago
6 0

Answer:

F = 0.00156[N]

Explanation:

We can solve this problem by using Newton's proposed universal gravitation law.

F=G*\frac{m_{1} *m_{2} }{r^{2} } \\

Where:

F = gravitational force between the moon and Ellen; units [Newtos] or [N]

G = universal gravitational constant = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1= Ellen's mass [kg]

m2= Moon's mass [kg]

r = distance from the moon to the earth [meters] or [m].

Data:

G = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1 = 47 [kg]

m2 = 7.35 * 10^22 [kg]

r = 3.84 * 10^8 [m]

F=6.67*10^{-11} * \frac{47*7.35*10^{22} }{(3.84*10^8)^{2} }\\ F= 0.00156 [N]

This force is very small compare with the force exerted by the earth to Ellen's body. That is the reason that her body does not float away.

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A car is traveling at a velocity of 22 m/s when the driver puts on the brakes
Brums [2.3K]

The car’s velocity at the end of this distance is <em>18.17 m/s.</em>

Given the following data:

  • Initial velocity, U = 22 m/s
  • Deceleration, d = 1.4 m/s^2
  • Distance, S = 110 meters

To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

V^2 = U^2 + 2dS

Substituting the values into the formula, we have;

V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}

<em>Final velocity, V = 18.17 m/s</em>

Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>

<em></em>

Read more: brainly.com/question/8898885

8 0
2 years ago
Serena drops a 5-kg book down the stairwell. What is the book's final velocity vf after it falls
elena55 [62]

Answer:

39.2m/s

Explanation:

Given parameters:

Mass of book  = 5kg

Time taken for fall  = 4s

Unknown:

Final velocity of the book  = ?

Solution:

Serena dropped the book from rest therefore, the initial velocity of the book is 0.

 Let us find the appropriate motion equation to solve this problem;

        V  = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity  = 9.8m/s²

t is the time taken

  Insert the given parameters and solve;

       V = 0 + 9.8 x 4  = 39.2m/s

3 0
3 years ago
2 pts
const2013 [10]

Answer:

I think the answer 1

Explanation:

im probably wrong too i dont know

5 0
3 years ago
If you represent velocity with an arrow, the length of the arrow represents -
Mamont248 [21]

Answer:

direction

Explanation:

3 0
3 years ago
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A train travels 90 kilometers in 1 hour, and then 82 kilometers in 5 hours. What is it’s average speed?
PIT_PIT [208]
Distance is 90km,time 1 hr
distance 2 is 82km,time 5 hrs
average speed=total distance travelled/total time taken.
90+82=172/5+1=6
average speed=28.7km over hour
4 0
3 years ago
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