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Keith_Richards [23]
3 years ago
8

The photosphere refers to the Sun's: core atmosphere surface magnetic field

Physics
2 answers:
Rudiy273 years ago
6 0

Answer:

The photosphere is the visible "surface" of the sun. So your answer would be C.

Explanation: its right

bonufazy [111]3 years ago
4 0
I think it is magnetic field
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Molecules are bonded together in which of the following states of matter?
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Difference between elastic and inelastic collisions
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Where on a roller coaster is centripetal forces at work.
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2 years ago
you are about to work some magic with matter. you have a rectangular cube of matter in its solid state. it measures 3 in x 4 in
Elenna [48]

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

The matter in gaseous state can be expanded to occupy the volumes of the container.

<h3>Volume of each of the container</h3>

The volume of each of the container is calculated as follows;

<h3>Volume of the rectangular container</h3>

V = 5 in x 6 in x 3 in

V = 90 in³

<h3>Volume of the cylindrical container</h3>

V = πr²h

V = (π)(2.5 in)²(8 in)

V = 157.1 in³

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Vm = 60 in³

<h3>Matter in solid and liquid state</h3>

Matter has fixed volume in solid and liquid state.

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

<h3>Matter in gaseous state</h3>

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The matter in gaseous state can be expanded to occupy the volumes of the container.

Learn more about states of matter here:

#SPJ1

6 0
1 year ago
Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The f
Pavlova-9 [17]

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

<u>a) Determine the principal stresses and shear stress</u>

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

3 0
3 years ago
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