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Reil [10]
3 years ago
10

If the energy of a photon is 1.32 × 10¯18 j, what is its wavelength in nm?

Physics
2 answers:
Katarina [22]3 years ago
8 0
I think I remember hold on let me see if I can solve it
son4ous [18]3 years ago
8 0

Answer:

A

Explanation:

The energy E of a photon is

directly proportional to its frequency f by E = hf, where h is Planck's constant (above)

and the wavelength w is inversely proportional to the frequency by w = c/f, so we have

E related to w by: E = hc/w. Since h and c are constants, their product hc is constant

being 1.989 * 10**-25 joule-meters. So if we know E is 1.32 * 10**-18 J, we have:

1.32 * 10**-18 = (1.989 * 10**-25) / w or w = (1.989 * 10**-25) / (1.32 * 10**-18) Doing

the division and we find w = 1.507 x 10-7 meters, or 150.7 nanometers. (ultraviolet)

A. 150 x 10-7nm

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When two waves in the same medium hit each other, the resulting displacement of the medium is
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Answer:

1. Either larger or smaller than the displacement of either wave acting alone, depending on the signs of the displacements of the two waves.

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3 years ago
A projectile is launched at an angle of 36.7 degrees above the horizontal with an initial speed of 175 m/s and lands at the same
Softa [21]

Answer:

a) The maximum height reached by the projectile is 558 m.

b) The projectile was 21.3 s in the air.

Explanation:

The position and velocity of the projectile at any time "t" is given by the following vectors:

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

v = (v0 · cos α, v0 · sin α + g · t)

Where:

r = position vector at time "t"

x0 = initial horizontal position

v0 = initial velocity

t = time

α = launching angle

y0 = initial vertical position

g = acceleration due to gravity (-9.80 m/s² considering the upward direction as positive).

v = velocity vector at time t

a) Notice in the figure that at maximum height the velocity vector is horizontal. That means that the y-component of the velocity (vy) at that time is 0. Using this, we can find the time at which the projectile is at maximum height:

vy = v0 · sin α + g · t

0 = 175 m/s · sin 36.7° - 9.80 m/s² · t

-  175 m/s · sin 36.7° /  - 9.80 m/s² = t

t = 10.7 s

Now, we have to find the magnitude of the y-component of the vector position at that time to obtain the maximum height (In the figure, the vector position at t = 10.7 s is r1 and its y-component is r1y).

Notice in the figure that the frame of reference is located at the launching point, so that y0 = 0.

y = y0 + v0 · t · sin α + 1/2 · g · t²

y = 175 m/s · 10.7 s · sin 36.7° - 1/2 · 9.8 m/s² · (10.7 s)²

y = 558 m

The maximum height reached by the projectile is 558 m

b) Since the motion of the projectile is parabolic and the acceleration is the same during all the trajectory, the time of flight will be twice the time it takes the projectile to reach the maximum height. Then, the time of flight of the projectile will be (2 · 10.7 s) 21.4 s. However, let´s calculate it using the equation for the position of the projectile.

We know that at final time the y-component of the vector position (r final in the figure) is 0 (because the vector is horizontal, see figure). Then:

y = y0 + v0 · t · sin α + 1/2 · g · t²

0 = 175 m/s · t · sin 36.7° - 1/2 · 9.8 m/s² · t²

0 = t (175 m/s ·  sin 36.7 - 1/2 · 9.8 m/s² · t)

0 = 175 m/s ·  sin 36.7 - 1/2 · 9.8 m/s² · t

-  175 m/s ·  sin 36.7 / -(1/2 · 9.8 m/s²) = t

t = 21.3 s

The projectile was 21.3 s in the air.

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3 years ago
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light waves. the other waves like gamma rays or infrared waves or radio waves are all not visible to the eye. light is the only thing out of those you can see.

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Less because now there is less force on the scale and you are unbalanced. Therefore the scale will have a lower number then before.

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Answer:

Sound energy to electric energy - a person talking into a microphone

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Explanation:

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