Help pleaseeee 5/7 - 4/3 WILL MARK BRAINLIEST + 13 POINTS

5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?

Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0

2 years ago

what is the width of a rectangular prism when the surface area is 904 square feet, and it has a height of 10 feet and a length o

k0ka [10]

Answer:

The answer

Step-by-step explanation:

the width of a rectangular prism which has a height of 10 feet and a length of 14 feet should be 140 square feet

7 0

3 years ago

In a random sample, 10 students were asked to compute the distance they travel one way to school to the nearest tenth of a mile.

elixir [45]

Answer:

Mean = 3.12, Variance = 3.324, Standard deviation = 1.8232

Step-by-step explanation:

Total number of students = 10 students.

Given data, 1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

To find the mean, at first we have to take the sum of all given data and then divide with the number of students.

Let the data is X, = 1.1, + 5.2, + 3.6, + 5.0, + 4.8, + 1.8, + 2.2, + 5.2, + 1.5, + 0.8 = 31.2

Mean = 31.2 / 10 = 3.12

$\text{Standard deviation, S} = \sqrt{\frac{\sum x^{2} - \left [ (\sum x)^{2}/n \right ]}{n-1}} \\S = 1.8232 \\\rm The \ Variance = S^{2} = 3.324$

5 0

2 years ago

Neal opened a savings account 11 years ago with a deposit of $2,335.69. The account has an interest rate of 4.3% compounded dail

Vinvika [58]

Answer: $1,412.52

Step-by-step explanation:

Formula to calculate the accumulated amount if P principal invested for t years at a rate of interest r that compounded daily is given by:-

$A=P(1+\dfrac{r}{365})^{365t}$

Given: P= $2,335.69

r= 4.3%= 0.043

t= 11 years

Then,

$A=2335.69(1+\dfrac{0.043}{365})^{365\times11}\\\\=2335.69(1+0.000117808219178)^{4015}\\\\=2335.69(1.000117808219178)^{4015}\\\\= 2335.69(1.6047566747)\\\\=3748.09044309\approx3748.21\\\\\Rightarrow\ A=\$3748.21$

Interest earned = A-P

= $3748.21- 2335.69.

= $1412.52

Hence, Neal earned $1,412.52 as interest.

8 0

2 years ago

1.) What is the measure of ∠K, to the nearest degree?

lora16 [44]

We know that
the law of sines establish
a/sin A=b/sin B

problem N 1

50/sin K=53/sin 76-------> 50*sin 76=53*sin K-----> sin K=50*sin 76/53
sin K=0.9154
K=arc sin (0.9154)--------> K=66.25°------> K=66°

the answer problem N 1 is the option
c.) 66°

Problem N 2

30/sin R=35/sin 69------> sin R=30*sin 69/35-----> sin R=0.8002
R=arc sin(0.8002)-------> R=53.15°-----> R=53°

the answer problem N 2 is the option
b.) 53°

5 0

3 years ago

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