Answer:
1. is 25
2. I think this one is 25 too?
Step-by-step explanation:
im working on the second
x + 7 = 2(3x - 4) Remove the brackets
x + 7 = 2*3x - 4*2
x + 7 = 6x - 8 Subtract 7 from both sides.
x + 7 - 7 = 6x - 8 - 7
x = 6x - 15 Subtract 6x from both sides
x - 6x = - 15
-5x = - 15 Divide by -5
-5x/-5 = -15/-5
x = 3
Answer:
|GH| = 5,7 cm
Step-by-step explanation:
To know |GH|, you first need to find the length of |GD|.
We can calculate |GD| by;
cosG = |GC| / |GD|
<=> |GD| = |GC| / cosG
=> |GD| = 3,9 cm/ 0,62 = 6,33 cm
We now can easily calculate |GH| with the sinus of angle D;
sinD = |GH| / |GD|
<=> |GH| = sinD.|GD|
=> |GH| = 0,899.6,33 cm = 5,694 cm => 5,7 cm
I hope i did not make a mistake ...
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
