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3 years ago

I would like to know why this is the correct answer

Physics

1 answer:

Marta_Voda [28]3 years ago

4 0

Answer:

see below

Explanation:

First, the obvious, as you press the gas pedal harder the acceleration goes up as well. Conversely, is you do not press the pedal, you will not accelerate. This determines that is I press the gas pedal, it will CAUSE the car to accelerate. This proves causation.

Now, correlation. The definition of correlation in statistics is any statistical relationship between two random variables or data. This simply means that these two events are connected to one another. A POSITIVE correlation is when two correlated events move in the same direction as one another. I have added a graph to help visualize this. In this problem as the gas is pressed harder, the acceleration increases. If the pressure on the pedal was decreased, then the acceleration also decreases. If the pressure on the pedal is constant, the the acceleration is constant.

I hope this helps!

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Option (c) u0

Explanation:

The escape velocity has a formula as:

V = √(2gR)

Where V is the escape velocity,

g is the acceleration due to gravity

R is the radius of the earth.

Now, from the question, we were told that the escape velocity for the rocket taking off from earth is u0 i.e

V(earth) = u0

V(earth) = √(2gR)

u0 = √(2gR) => For the earth

Now, let us calculate the escape velocity for the rocket taking off from planet x. This is illustrated below below:

g(planet x) = 2g (earth) => since the weight of the astronaut is twice as much on planet x as on earth

R(planet x) = 1/2 R(earth) => planet x has half the radius of earth

V(planet x) =?

Applying the formula V = √(2gR), the escape velocity on planet x is obtained as follow:

V(planet x) = √(2g(x) x R(x))

V(planet x) = √(2 x 2g x 1/2R)

V(planet x) = √(2 x g x R)

V(planet x) = √(2gR)

The expression obtained for the escape velocity on planet x i.e V(planet x) = √(2gR), is exactly the same as that obtained for the earth i.e V(earth) = √(2gR)

Therefore,

V(planet x) = V(earth) = √(2gR)

But from the question, V(earth) is u0

Therefore,

V(planet x) = V(earth) = √(2gR) = u0

So, the escape velocity on planet x is u0

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4 years ago