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USPshnik [31]
3 years ago
14

I would like to know why this is the correct answer

Physics
1 answer:
Marta_Voda [28]3 years ago
4 0

Answer:

see below

Explanation:

First, the obvious, as you press the gas pedal harder the acceleration goes up as well.  Conversely, is you do not press the pedal, you will not accelerate.  This determines that is I press the gas pedal, it will CAUSE the car to accelerate.  This proves causation.

Now, correlation.  The definition of correlation in statistics is any statistical relationship between two random variables or data.  This simply means that these two events are connected to one another.  A POSITIVE correlation is when two correlated events move in the same direction as one another.  I have added a graph to help visualize this.  In this problem as the gas is pressed harder, the acceleration increases.  If the pressure on the pedal was decreased, then the acceleration also decreases.  If the pressure on the pedal is constant, the the acceleration is constant.

I hope this helps!

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A 3.5 kW drill transfers 5 000 kJ of kinetic energy during 15 seconds of use. What is the percentage efficiency of the drill?
Marizza181 [45]

Answer:

1.04%

Explanation:

Given that,

The power of drill = 3.5 kW = 3500 W

Transferred kinetic energy = 5000 kJ during 15 seconds of use.

We need to find the percentage efficiency of the drill. It can be given by :

\eta=\dfrac{P_o}{P_i}\times 100

Where

Po and Pi are output and input powers.

P_o=\dfrac{5000\times 10^3}{15}\\\\=3.34\times 10^5\ W

So,

\eta=\dfrac{3500}{3.34\times10^{5}}\times100\\\\=1.04\%

So, the percentage efficiency of the drill is 1.04%.

4 0
3 years ago
Quanto vale a resultante de duas forças de mesmo módulo mesma direção e sentidos opostos atuando sobre um corpo de massa igual a
Crank
A resultante das duas forças será zero, já q os sentidos são opostos e sãos iguais em módulo, elas se anulam. Logo, se a força resultante é zero, e F=ma, aceleração também será igual a zero.
6 0
4 years ago
Read 2 more answers
1.The putt shot is used for hitting the golf ball off of the golf tee.
MArishka [77]

Answer:

1.True 2.

Explanation:

3 0
3 years ago
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if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring
Aleksandr-060686 [28]
So what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)
    
here ,
energy required = 10.0°C                Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C    Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= \frac{10}{3.1*17.9}
 
                                   = 0.1802126509
      
                                   = 0.1802 cal./g°C            <span>i rounded the answer to the                                                                                      fourth decimal point
</span>



6 0
3 years ago
A car moving 18.2 m/s starts to coast up a frictionless 10.0 degree hill. how far does it roll before coming to a stop
Kazeer [188]

The distance covered by the car before it stops is 98.58 m.

<h3>Calculation:</h3>

Force acting on the car will be

ma = -mg sinθ

where,

m = mass of the car

a = acceleration of the car

g = acceleration due to gravity

θ = angle of inclination

Given,

θ = 10°

Put the values in the above equation,

ma = -mg sinθ

a = -g sin 10°

a = -10 (0.173)

a = -1.73 m/s²

We know the initial velocity is 18.2m/s and when the car comes to a stop the final velocity becomes zero.

u = 18.2 m/s

v= 0 m/s

Using one of the kinematics equations,

v² - u² = 2as

0 - (18.2)² = 2 (-1.73) (s)

331.24 = 3.36 (s)

s = 98.58 m

Hence, the distance covered by the car before it stops is 98.58 m.

Learn more about the other way to solve such numerical here:

brainly.com/question/12985617

#SPJ4

8 0
2 years ago
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