Given what we know, we can confirm that as Halley's comet moves closer to the sun, we can expect its potential energy to be near its maximum.
<h3>How do we know this?</h3>
We can conclude that its potential energy will increase as it comes closer to the sun, and will reach its maximum at the closest point to the sun. This is because the potential energy of an object is directly proportional to the force of gravity acting on that object. As Halley's comet approaches the sun, the sun's gravitational pull on the comet is stronger, and thus, its potential energy increases.
Therefore, given the relationship between gravity and potential energy, we can confirm that s Halley's comet moves closer to the sun, we can expect its potential energy to increase and be near its maximum.
To learn more about potential energy visit:
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Answer:
Explanation:
Given
Initial Flow of water![=100 ft^3/s](https://tex.z-dn.net/?f=%3D100%20ft%5E3%2Fs)
density ![\rho =62.4 lbm/ft^3](https://tex.z-dn.net/?f=%5Crho%20%3D62.4%20lbm%2Fft%5E3)
Initial velocity![(v_i)=20 ft/s](https://tex.z-dn.net/?f=%28v_i%29%3D20%20ft%2Fs)
Final velocity ![(v_f)=18 ft/s](https://tex.z-dn.net/?f=%28v_f%29%3D18%20ft%2Fs)
Initial mass flow rate![=\rho Av=\rho Q](https://tex.z-dn.net/?f=%3D%5Crho%20Av%3D%5Crho%20Q)
![m_i=62.4\times 100=62.4\times 10^2 lbm/s](https://tex.z-dn.net/?f=m_i%3D62.4%5Ctimes%20100%3D62.4%5Ctimes%2010%5E2%20lbm%2Fs)
Let area of cross section of Two streams after striking be A
Conserving Flow
![Q_i=Q_1+Q_2](https://tex.z-dn.net/?f=Q_i%3DQ_1%2BQ_2)
![100=A\times 18+A\times 18](https://tex.z-dn.net/?f=100%3DA%5Ctimes%2018%2BA%5Ctimes%2018)
![A=\frac{50}{18} ft^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B50%7D%7B18%7D%20ft%5E2)
or Flow rate after splitter splits in to half
![Q_i=2Q_f](https://tex.z-dn.net/?f=Q_i%3D2Q_f)
conserving momentum in x direction
Final momentum in x direction ![=m\times v](https://tex.z-dn.net/?f=%3Dm%5Ctimes%20v)
![P_f=2\times \rho \frac{Q}{2}\times 18\times \cos 45](https://tex.z-dn.net/?f=P_f%3D2%5Ctimes%20%5Crho%20%5Cfrac%7BQ%7D%7B2%7D%5Ctimes%2018%5Ctimes%20%5Ccos%2045)
![P_i=\rho Q\times 20](https://tex.z-dn.net/?f=P_i%3D%5Crho%20Q%5Ctimes%2020)
Change in momentum![=P_i-P_f](https://tex.z-dn.net/?f=%3DP_i-P_f)
![=20\rho \times Q-\frac{18\rho Q}{\sqrt{2}}](https://tex.z-dn.net/?f=%3D20%5Crho%20%5Ctimes%20Q-%5Cfrac%7B18%5Crho%20Q%7D%7B%5Csqrt%7B2%7D%7D)
![=7.28\times 62.4\times 100](https://tex.z-dn.net/?f=%3D7.28%5Ctimes%2062.4%5Ctimes%20100)
![=45,427.2 lbm-ft/s^2](https://tex.z-dn.net/?f=%3D45%2C427.2%20lbm-ft%2Fs%5E2)
F=1409.24 lbf
change of momentum in Y direction is zero as the two flows oppose thier motion after striking with splitter.
Answer:
It’s mass would be the same
Explanation:
Mass and weight are often used interchangeably in everyday conversation. For example, our medical records often show our weight in kilograms but never in the correct units of newtons. In physics, however, there is an important distinction. Weight is the pull of Earth on an object. It depends on the distance from the center of Earth. Unlike weight, mass does not vary with location. The mass of an object is the same on Earth, in orbit, or on the surface of the Moon.
It's B.
It's never going to be true UNLESS you cooled the entire thing to below zero then it could be true.
Answer: 380km due south
Explanation:
Velocity is the rate of change of displacement. Mathematically
Velocity = displacement/time taken
Displacement = Velocity×time taken
Given velocity = 73km/hr
Time taken = 5.2hrs
Displacement = 73km/hr×5.2hrs
Displacement = 379.6km
Approximately 380km due South