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Musya8 [376]
2 years ago
9

A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long a

s 2.20 m have been recorded. If a frog jumps 2.20 m and the launch angle is 36.5°, find the frog's launch speed and the time the frog spends in the air. Ignore air resistance.
(a)the frog's launch speed (in m/s)

(b)the time the frog spends in the air (in s)
Physics
1 answer:
IrinaK [193]2 years ago
4 0

The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

To find the answer, we need to know about the time of flight and range of projectile motion.

<h3>What's the expression of range of a projectile motion?</h3>
  • Range = U²× sin(2θ)/g
  • U= initial velocity, θ= angle of projectile and g= acceleration due to gravity
  • U=√{Range×g/sin(2θ)}
  • Here, range= 2.20m, = 36.5°
  • U= √{2.20×9.8/sin(73)}

U= √{2.20×9.8/sin(73)} = 22.5m/s

<h3>What's the expression of time of flight in projectile motion?</h3>
  • Time of flight= (2×U×sinθ)/g
  • So, T= (2×22.5×sin36.5°)/9.8

= 2.73 s

Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

Learn more about the range and time period of projectile motion here:

brainly.com/question/24136952

#SPJ1

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When talking about the speeds of atoms in a gas you must refer to the average speed because
cluponka [151]

Answer:

An Atom's individual speed will change as it collides with other atoms, so we have to use an average.

Explanation:

In a gas a single atoms does an assortment of things during its time in the gas—sometimes it collides with an other atom gaining a lot of speed, sometimes losing a lot of speed in the collision, and sometimes just moving freely. Therefore: the motion of one individual atom is unpredictable, and it cannot be  representative of all the the atoms in a gas, which is why we must average over all speeds of all atoms to find an average speed that allows us to calculate other quantities like temperature and pressure of the gas.

Hence, the second option <em>"an Atom's individual speed will change as it collides with other atoms, so we have to use an average" </em>stands correct.

3 0
2 years ago
If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.8 ss , how far do you travel during this ina
pashok25 [27]

Answer:

Distance = 70 meters

Explanation:

<u>Given the following data;</u>

Speed = 90 km/h

Time = 2.8 seconds

<u>Conversion:</u>

90 km/h to meters per seconds = 90 * 1000/3600 = 90000/3600 = 25 m/s

To find the distance covered during this inattentive period;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

Speed = \frac{distance}{time}

Making distance the subject of formula, we have;

Distance = speed * time

Substituting into the above formula, we have;

Distance = 25 * 2.8

<em>Distance = 70 meters</em>

5 0
2 years ago
If the inside of a container has a surface area of 20cm², what will be the pressure on each square inch of the container if 117.
egoroff_w [7]

Answer:

Explanation:

given :-

force applied = 117.6N

Area = 20 m^2

Pressure =?

solution:-

Pressure = Force / Area

= 117.6 N / 20 m^2

= 5.88 Pascals

Hope it helps :D!

Explanation:

6 0
1 year ago
Check my answer(there’s one above) I really just chose my best guess on this.for the ones below, can you provide a simple explan
almond37 [142]

#1

For closed pipe the fundamental frequency will be given as

f = \frac{v}{4L}

153 = \frac{340}{4L}

L = 0.56 m

L = 55 cm

#2

For open pipe the wavelength for Nth harmonic will be given as

n \times \frac{\lambda}{2} = L

\lambda = \frac{2L}{n}

#3

for a closed pipe the frequency is given as

f = \frac{nv}{4L}

here for third harmonic n = 3

f = \frac{3v}{4L}

now plug in all values

235 = \frac{3\times 340}{4L}

L = 1.09 m

L = 109 cm

#10

since in the given figure there are three complete loops

so in this case the <em>number of harmonics are THREE</em>

3 0
3 years ago
How much water is displaced by a solid object with a volume of 9 cm3 that is completely submerged in the water?
Sati [7]

Given :

An object with a volume of 9 cm³ is completely submerged in the water.

To Find :

How much water is displaced by the object.

Solution :

According to Archimedes' principle, the amount of volume displaced of fluid when an object is fully and partially submerged into that is equal to the volume of the object below the surface of liquid.

Now, it is given that object is fully submerged into water.

Therefore, volume of water displaced by the object is 9 cm³.

6 0
2 years ago
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