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Lady_Fox [76]
3 years ago
12

In 2004 astronomers reported the discovery of a large Jupiter-sized planet orbiting very close to the star HD 179949 (hence the

term "hot Jupiter"). The orbit was just 19 the distance of Mercury from our sun, and it takes the planet only 3.09 days to make one orbit (assumed to be circular). What is the mass of the star? Express your answer (a)in kilograms and (b)as a multiple of our sun's mass.
Physics
1 answer:
sp2606 [1]3 years ago
6 0
  <span>I'll tell you how to do it but you must crunch the numbers. 

Use Kepler's 3rd Law 

T^2 = k R^3 

where k = 4(pi)^2/ GM 
G =gravitational constant = 6.67300 × 10-11 m3 kg-1 s-2 
M = mass of this new planet 
pi = 3.14159265 
T =3.09 days = 266976 seconds 
R = (579,000,000km)/9 = 64333333.3 km 

a) 
Solve Kepler's 3rd Law for M. Your answer will be in kg 


b) 
mass of the sun = 1.98892 × 10^30 kilograms 
Form the ratio 
M(planet)/M(sun) </span>
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Answer:

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Explanation:

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3 years ago
Spaceship 1 and Spaceship 2 have equal masses of 300kg. They collide. Spaceship 1's final speed is 3 m/s, and Spaceship 2's fina
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Answer:

B. 1500 kg*m/s

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p1 + p2 =

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3 years ago
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2 years ago
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What is the temperature of a 3.72 mm cube (e=0.288) that radiates 56.6 W?
blsea [12.9K]

Answer:

The temperature is 2541.799 K

Explanation:

The formula for black body radiation is given by the relation;

Q = eσAT⁴

Where:

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A = Surface area of the cube = 6×(3.72 mm)² = 8.3 × 10⁻⁵ m²

e = emissivity = 0.288

T = Temperature

Therefore, we have;

T⁴ = Q/(e×σ×A) = 56.6/(5.67 × 10⁻⁸ × 8.3 × 10⁻⁵ × 0.288) = 4.174 × 10¹⁴ K⁴

T  =  2541.799 K

The temperature = 2541.799 K.

7 0
3 years ago
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